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charle [14.2K]
3 years ago
9

A and B take M days to complete a task together if A takes 27 days more than A and B to complete the task alone. And if B takes

3 days more than A and B can do the job alone, what is the value of M?​
Mathematics
1 answer:
Juliette [100K]3 years ago
7 0

Answer:

9 days.

hope it helps

Step-by-step explanation:

As per given data

1/x=1/(x+27)+1/(x+3)

1/x=(x+3+x+27)/(x+27)(x+3)

X^2+30x+81=2x^2+30x

X^2=81

X=9

so A&B can together do the work in 9 days

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Plz help its due TOMMOROW​
sashaice [31]

Answer:

  86%

Step-by-step explanation:

Let g represent the mean mark for the 10 girls in the class. Then the mean mark for the class was ...

  10g +20(62%) = 30(70%)

  g = 3(.7) -2(.62) . . . . . . . . . divide by 10 and subtract 2(.62)

  g = .86 = 86%

The mean mark for girls was 86%.

_____

You can do this in your head if you consider it in terms of deviations from the mean. The second equation above can be rewritten and factored as ...

  g = 70% +2(70% -62%)

That is, because there are 2 boys for every girl, the girl's score is above the mean by an amount that is 2 times the amount that the boy's score is below the mean. The boys' score is below by 8%, so the girls' score is above by 16%, so is 86%.

4 0
2 years ago
Three boxes of cereal have masses of 268.5 grams, 513.25 grams, and 288.37 grams. ​What is the difference between the box of cer
creativ13 [48]
The difference is 244.75
4 0
3 years ago
2 Here are two equations:
MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

<u>i (3,4) </u>

Putting in Equation 1:

6(3) + 4(4) = 34\\18+16=34\\34=34\\

Putting in Equation 2:

5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15

<u>ii. (4,2.5)</u>

Putting in Equation 1:

6(4) + 4(2.5) = 34\\24+10=34\\34=34\\

Putting in Equation 2:

5(4) - 2(2.5) = 15\\20-5 = 15\\15=15

<u>ill. (5,5)</u>

6(5) + 4(5) = 34\\30+20=34\\50\neq 34

Putting in Equation 2:

5(5) - 2(5) = 15\\25-10 = 15\\15=15

<u>iv. (3,2)</u>

6(3) + 4(2) = 34\\18+8=34\\26\neq 34

Putting in Equation 2:

5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

  • brainly.com/question/10534381
  • brainly.com/question/10538663

#LearnwithBrainly

8 0
3 years ago
If (6y − 11)(6y 11) = ay^2 − b, what is the value of a? the value of a is ____________.
Triss [41]
(6y - 11)(6y + 11) = ay² - b    |use (a - b)(a + b) = a² - b²

(6y)² - 11² =ay² - b

36y² - 121 = ay² - b    |add b to both sides

ay² = 36y² - 121 + b        |divide both sides by y² ≠ 0

a = (36y² - 121 + b)/y²

\boxed{a=\dfrac{36y^2-121+b}{y^2}}
7 0
3 years ago
Which expression is equivalent to 18s+9t+36
tatuchka [14]

18(s+t/2+2)

18(s+t/2+2)

8 0
3 years ago
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