Which function is an even function?

Advantage of this app?

Morgarella [4.7K]

You get an answer to your question really quick,
...like now!

3 0

2 years ago

Read 2 more answers

Sorry again. really really sorry. help.

natali 33 [55]

Answer:

No, it is not correct the answer is 156.06

Step-by-step explanation:

5.1 × 5.1 is 26.01

26.01 × 6 is 156.06

3 0

2 years ago

Read 2 more answers

(x=1)^2-4x=(x-1)^2 simplify and answer

Dennis_Churaev [7]

Step-by-step explanation:

Firstly, there's a typing error at (x=1)². I assume it is (x-1)². If my assumption is correct,then:

x²-2x+1-4x=x²-2x+1

x²-6x+1-x²+2x-1=0

-4x=0

x=0

5 0

2 years ago

A motorboat takes 5 hours to travel 100 kilometers going upstream. The return trip takes

tatuchka [14]

Step-by-step explanation:

Let's say b is the rate of the boat in still water, and c is the rate of the current.

Distance = rate × time

Going upstream:

100 = (b − c) (5)

20 = b − c

Going downstream:

100 = (b + c) (2)

50 = b + c

Solve the system of equations using substitution or elimination. Using elimination, add the equations together:

70 = 2b

b = 35

c = 15

The boat's speed is 35 km/h, and the current's speed is 15 km/h.

8 0

3 years ago

Calculate the sample standard deviation and sample variance for the following frequency distribution of hourly wages for a sampl

lidiya [134]

Answer:

(a) The sample variance is 16.51

(a) The sample standard deviation is 4.06

Step-by-step explanation:

Given

$\begin{array}{cc}{Class} & {Frequency} & 8.26 - 10.00 & 20 &10.01-11.75 & 38 &11.76 - 13.50& 36 & 13.51-15.25 &25&15.26-17.00 &27 &\ \end{array}$

Solving (a); The sample variance.

First, calculate the class midpoints.

This is the mean of the intervals.

i.e.

$x_1 = \frac{8.26+10.00}{2} = \frac{18.26}{2} = 9.13$

$x_2 = \frac{10.01+11.75}{2} = \frac{21.76}{2} = 10.88$

$x_3 = \frac{11.76+13.50}{2} = \frac{25.26}{2} = 12.63$

$x_4 = \frac{13.51+15.25}{2} = \frac{28.76}{2} = 14.38$

$x_5 = \frac{15.26+17.00}{2} = \frac{32.26}{2} = 16.13$

So, the table becomes:

$\begin{array}{ccc}{Class} & {Frequency} & {x} & 8.26 - 10.00 & 20&9.13 &10.01-11.75 & 38 &10.88&11.76 - 13.50& 36 &12.63& 13.51-15.25 &25&14.38&15.26-17.00 &27 &16.13\ \end{array}$

Next, calculate the mean

$\bar x = \frac{\sum fx}{\sum f}$

$\bar x = \frac{20*9.13 + 38 * 10.88+36*12.63+25*14.38+27*16.13}{20+38+36+25+27}$

$\bar x = \frac{1845.73}{146}$

$\bar x = 12.64$

Next, the sample variance is:

$\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}$

So, we have:

$\sigma^2 = \frac{20*(9.13-12.63)^2 + 38 * (10.88-12.63)^2 +...........+27 * (16.13 -12.63)^2}{20+38+36+25+27-1}$

$\sigma^2 = \frac{2393.6875}{145}$

$\sigma^2 = 16.51$

The sample standard deviation is:

$\sigma = \sqrt{\sigma^2}$

$\sigma = \sqrt{16.51}$

$\sigma = 4.06$

6 0

2 years ago