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2 years ago

Try to answer the following question without running the code in Python:

Mathematics

1 answer:

zloy xaker [14]2 years ago

5 0

The value of x is an int with value 1.

The correct option is (A).

<h3>What is / in python?</h3>

Divides the value on the left by the one on the right.

<h3>What is // in python?</h3>

Divides and returns the integer value of the quotient.

x= 8/4//2

x= 2//2

x=1

Learn more about operators in python here:

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I have a math project i need help with!?!?

Vlada [557]

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Chevy- 63,360 divided by 113.04= 560.5 times 10,000=5,605,000 rotations per mile
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4 years ago

What is the solution of 10=|7-3x|

Tom [10]

$10=|7-3x| \\ 7-3x=10 \vee 7-3x=-10\\ 3x=-3 \vee 3x=17\\ x=-1 \vee x=\dfrac{17}{3}$

5 0

3 years ago

which equation represents an exponential function that passes through the point (2, 80)? f(x) = 4(x)5 f(x) = 5(x)4 f(x) = 4(5)x

pav-90 [236]

we know that

if the exponential function passes through the given point, then the point must satisfy the equation of the exponential function

we proceed to verify each case if the point $(2,80)$ satisfied the exponential function

<u>case A</u> $f(x)=4(x^{5})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

$f(2)=4(2^{5})=128$

$128\neq 80$

therefore

the exponential function $f(x)=4(x^{5})$ not passes through the point $(2,80)$

<u>case B</u> $f(x)=5(x^{4})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

$f(2)=5(2^{4})=80$

$80=80$

therefore

the exponential function $f(x)=5(x^{4})$ passes through the point $(2,80)$

<u>case C</u> $f(x)=4(5^{x})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

$f(2)=4(5^{2})=100$

$100\neq 80$

therefore

the exponential function $f(x)=4(5^{x})$ not passes through the point $(2,80)$

<u>case D</u> $f(x)=5(4^{x})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

$f(2)=5(4^{2})=80$

$80=80$

therefore

the exponential function $f(x)=5(4^{x})$ passes through the point $(2,80)$

therefore

<u>the answer is</u>

$f(x)=5(x^{4})$

$f(x)=5(4^{x})$

7 0

3 years ago

G(n)=n2-5n; find g(-8)

azamat

G(-8)=(-8)^2-5(-8)
=64+40
g(-8)=104

4 0

3 years ago

Read 2 more answers

The rate constant for this first‑order reaction is 0.740 s − 1 0.740 s−1 at 400 ∘ C. 400 ∘C. A ⟶ products A⟶products How long, i

sesenic [268]

Answer:

1.668 S

Step-by-step explanation:

We are given that

$A\rightarrow$ Product

For first order reaction,

$t=\frac{1}{k}ln\frac{A_0}{A}$

$t=\frac{2.303}{k}log\frac{A_0}{A}$

Rate constant=k= $0.740s^{-1}$

Temperature= $T=400^{\circ}$

We have to find the time taken by the reaction when concentration of A to decrease from 0.790 M to 0.230 M.

$A_0=0.79 M$

$A=0.230$

Substitute the values then we get

$t=\frac{2.303}{0.740}log\frac{0.79}{0.23}$

$t=1.668 s$

Hence, it would take 1.668 s for the concentration of A to decrease from 0.790 M to 0.230 M.

4 0

4 years ago