3 years ago

Find the circumference of a circle whose diameter is 4

Mathematics

1 answer:

pantera1 [17]3 years ago

7 0

It'd be about 50.27 units

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Simplify the expression. Write the answer without using parentheses or negative exponents.

rodikova [14]

$\frac{ (x^4 y^2)^5 }{ (x^2 y)^2 } =\frac{ x^{4*5} y ^{2*5} }{ x ^{2*2} y ^2 } =\frac{ x^{20} y ^{10} }{ x^4y^2 } = x^{20-4} *y^{10-2}= x^{16} *y^{8}$

5 0

3 years ago

How do you do this problem?

faust18 [17]

The volume of the original cylinder is

... V = π·r²·h

For r=1 and h=1, this is

... V = π·1²·1 = π

For the new cylinder, the volume is 1.089 times that amount.

... V = 1.089π = π·1.1²·(1-k)

... 1.089/1.21 = 1-k

... k = 1 - 1.089/1.21 = 1 - 0.9 = 0.1 = 10%

The appropriate choice is (B) 10.

7 0

4 years ago

Read 2 more answers

11. Find the average rate of change of the equation y = x2 + 4x + 1 on the interval -1 < x < 4.

coldgirl [10]

Answer:

31/5

Step-by-step explanation:

[f(4) - f(-1)] / 4-(-1)

7 0

3 years ago

Thirty work orders are selected from a filing cabinet containing 500 work order folders by choosing every 15th folder. which sam

Andru [333]

It is Systematic sampling

5 0

3 years ago

What is the distance between the points (2,10) and (-6, 4) on the coordinate

stellarik [79]

Answer:

The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units

Therefore distance s=10 units

Step-by-step explanation:

Given points are (2,10) and (-6, 4) on the coordinate plane

To distance between the given points :

The distance formula is $s=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ units

Let $(x_1,y_1)$ , $(x_2,y_2)$ be the given points (2,10) and (-6, 4) respectively

Now substituting the values in the distance formula we get

$s=\sqrt{(-6-2)^2+(4-10)^2}$

$=\sqrt{(-8)^2+(-6)^2}$

$=\sqrt{8^2+6^2}$

$=\sqrt{64+36}$

$=\sqrt{100}$

$=10$

Therefore s=10 units

The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units

5 0

3 years ago