1.625 rounded to the nearest hundredth is 1.63
Refer to the diagram shown below. It shows a vertical cross-section of the paraboloid through its axis of symmetry.
Let the vertex of the parabola be at the origin. Then its equation is of the form
y = bx²
Because the parabola passes through (18,8), therefore
8 = b(18²)
b = 0.02469
The parabola is y = 0.02469x².
The receiver should be placed at the focal point of the paraboloid for optimal reception.
The y-coordinate of the focus is
a = 1/(4b) = 1/0.098765 = 10.125 in
Answer: The receiver is located at 10.125 inches from the vertex.
The the value of f(n)=
Step-by-step explanation:
The Arithemetic sequence is given as a,a+d,a+2d......a(n-1)d
and f(n)=a(n-1)d
The given sequence is 1/3,4/3,7/3...
By comapring with Arithemetic sequence,
we get a=1/3
a+d=4/3
1/3 + d = 4/3
d=1
To find value of f(10):
take n=10
f(n)=
f(n)=
f(n)=
f(n)=
Answer:
2,4,5
Step-by-step explanation: