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vladimir2022 [97]
2 years ago
14

Use the following equation to answer the following question

Chemistry
1 answer:
snow_tiger [21]2 years ago
8 0

Answer: nitrogen

Explanation:

  1. Converting 5.78 g of hydrogen to moles, we know that the formula mass of hydrogen is about 2(1.00794)=2.01588 g/mol, so 5.78 grams is about 5.78/2.01588=2.867 mol.
  2. Converting 6.28 g of nitrogen to moles, we know that the formula mass of nitrogen is about 2(14.0067)=28.0134 g/mol, so 6.28 grams is about 6.28/28.0134 = 0.22417 mol.

From the equation, we know that for every 3 moles of hydrogen consumed, 1 mole of nitrogen is consumed.

  • Considering the hydrogen, the reaction can occur 2.867/3=0.955 times.
  • Considering the nitrogen, the reaction can occur 0.22417 times.

Therefore, <u>nitrogen</u> is the limiting reactant.

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uysha [10]

Answer:

d. 12.3 grams of Al2O3

Explanation:

The balanced chemical equation of this chemical reaction is as follows:

4Al + 3O2 --> 2Al2O3

Based on the balanced equation, 4 moles of aluminum (limiting reagent) reacts to form 2 moles of aluminum oxide (Al2O3).

First, we need to convert the mass of aluminum to moles using the formula;

mole = mass/molar mass

Molar mass of Al = 27g/mol

mole = 6.50/27

= 0.241mol of Al.

Hence, if 4 moles of aluminum (limiting reagent) reacts to form 2 moles of aluminum oxide (Al2O3).

Then, 0.241mol of Al will produce (0.241 × 2/4) = 0.241/2 = 0.121mol of Al2O3.

Convert this mole value to molar mass using mole = mass/molar mass

Molar mass of Al2O3 = 27(2) + 16(3)

= 54 + 48

= 102g/mol

mass = molar mass × mole

mass = 102 × 0.121

mass of Al2O3 = 12.34grams.

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3 years ago
Classify this statement as always true, AT; sometimes true, ST; or never true, NT. To obtain a value for the number of moles usi
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AT, STP in chemistry is the abbreviation for Standard Temperature and Pressure. STP most commonly is used when performing calculations on gases, such as gas density
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How many feet are in 6.75 miles? <br><br> (6.75x1) divided by 5280 =
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Explanation:

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Number one is the question I need help on!
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Please refer to the attachment above.

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