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Svetllana [295]
2 years ago
14

When heated, KClO3 decomposes into KCl and O2. 2KClO3⟶2KCl+3O2 If this reaction produced 17.4 g KCl, how many grams of O2 were p

roduced? maSS
Chemistry
2 answers:
Allisa [31]2 years ago
8 0

Answer:

a car traveled 20m &400k/g

navik [9.2K]2 years ago
7 0

Answer:

12.6 g O2 or

12.60 g O2 (if needed two decimal places)

Explanation:

First convert grams into moles:

17.4 g KCl × <u> </u><u> </u><u> </u><u> </u><u> </u><u>1</u><u> </u><u> </u><u> </u><u> </u><u> </u>

74.55

= 0.233 moles of KCl

Next solve for the mole of O2:

= 0.233 × <u>3</u><u> </u><u>m</u><u>o</u><u>l</u><u>e</u><u>s</u><u> </u><u>o</u><u>f</u><u> </u><u>O</u><u>2</u>

2 moles of KCl

= 0.3495 or

= 0.350 moles of O2

Finally convert the mole to grams:

= 0.350 moles of O2 × <u> </u><u> </u><u> </u><u>36</u><u>g</u><u> </u><u> </u>

1 mole

= 12.6 g O2 or 12.60 g O2

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From these two reactions at 298 K, V2O3(s) + 3CO(g) → 2V(s) + 3CO2(g); ΔH° = 369.8 kJ; ΔS° = 8.3 J/K V2O5(s) + 2CO(g) → V2O3(s)
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