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3 years ago

Why are scientists worried that climate change will cause these toxic algae blooms to become more frequent?

Chemistry

2 answers:

stiv31 [10]3 years ago

7 0

Answer:

I would assume it would kill marine life and or a shift in the climate may possibly create a better environment for the algae to grow Don't quote me on that though I couldn't tell you

11Alexandr11 [23.1K]3 years ago

5 0

Answer:

It may kill marine life and or a shift in the climate might make better growth of algae possible.

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Which of the following best describes the uses of private land?

melamori03 [73]

Answer : (C) It can be used for variety of activities and 4es

Explanation: A private land is generally used for any purpose like home, business, office, factories or any other purpose. The land is privately owned by its owner which can use the private land for variety of activities the owner wants. A private land can be used as a farm land, or any other non agriculture purpose like building a factory, converting into home or any other purpose.

7 0

3 years ago

Read 2 more answers

Chloral hydrate (C2H3Cl3O2) is a drug formerly used as a sedative and hypnotic.

Dmitrij [34]

Answer :

(a) The molar mass of $C_2H_3Cl_3O_2$ is, 165.5 g/mole

(b) The moles of $C_2H_3Cl_3O_2$ is, 3.02 moles

(c) The mass in grams of $2.0\times 10^{-2}$ mole chloral hydrate is, 3.31 g

(d) The number of chlorine atoms in 5.0 g chloral hydrate is, $5.4\times 10^{22}$

(e) The mass of chloral hydrate will be, 1.55 g

(f) The mass of exactly 500 molecules of chloral hydrate is, $1.99\times 10^{23}$

Explanation :

(a) To calculate the molar mass of chloral hydrate.

The formula of chloral hydrate is, $C_2H_3Cl_3O_2$

Atomic mass of carbon = 12 g/mole

Atomic mass of hydrogen = 1 g/mole

Atomic mass of oxygen = 16 g/mole

Atomic mass of chlorine = 35.5 g/mole

Now we have to determine the molar mass of chloral hydrate.

$\text{Molar mass of }C_2H_3Cl_3O_2$ =2(12g/mole)+3(1g/mole)+3(35.5g/mole)+2(16g/mole)=165.5g/mole[/tex]

The molar mass of $C_2H_3Cl_3O_2$ is, 165.5 g/mole

(b) Now we have to determine the moles of $C_2H_3Cl_3O_2$ .

$\text{Moles of }C_2H_3Cl_3O_2=\frac{\text{Mass of }C_2H_3Cl_3O_2}{\text{Molar mass of }C_2H_3Cl_3O_2}=\frac{500.0g}{165.5g/mole}=3.02moles$

The moles of $C_2H_3Cl_3O_2$ is, 3.02 moles

(c) Now we have to determine the mass in grams of $2.0\times 10^{-2}$ mole chloral hydrate.

$\text{Mass of }C_2H_3Cl_3O_2=\text{Moles of }C_2H_3Cl_3O_2\times \text{Molar mass of }C_2H_3Cl_3O_2$

$\text{Mass of }C_2H_3Cl_3O_2=(2.0\times 10^{-2}mole)\times (165.5g/mole)=3.31g$

The mass in grams of $2.0\times 10^{-2}$ mole chloral hydrate is, 3.31 g

(d) To calculate the number of chlorine atoms are in 5.0 g chloral hydrate.

First we have to determine the moles of $C_2H_3Cl_3O_2$ .

$\text{Moles of }C_2H_3Cl_3O_2=\frac{\text{Mass of }C_2H_3Cl_3O_2}{\text{Molar mass of }C_2H_3Cl_3O_2}=\frac{5g}{165.5g/mole}=0.03moles$

Now we have to calculate the number of chlorine atoms in chloral hydrate.

In $C_2H_3Cl_3O_2$ , there are, 2 carbon atoms, 3 hydrogen atoms, 3 chlorine atoms and 2 oxygen atoms.

As, 1 mole of $C_2H_3Cl_3O_2$ contains $3\times 6.022\times 10^{23}$ chlorine atoms

So, 0.03 mole of $C_2H_3Cl_3O_2$ contains $0.03\times 3\times 6.022\times 10^{23}=5.4\times 10^{22}$ chlorine atoms

The number of chlorine atoms in 5.0 g chloral hydrate is, $5.4\times 10^{22}$

(e) To calculate the mass of chloral hydrate would contain 1.0 g Cl.

As, $3\times 35.5g$ of chlorine present in 165.5 g of $C_2H_3Cl_3O_2$

So, 1 g of chlorine present in $\frac{165.5}{3\times 35.5}=1.55g$ of $C_2H_3Cl_3O_2$

The mass of chloral hydrate will be, 1.55 g

(f) To calculate the mass of exactly 500 molecules of chloral hydrate.

As, $6.022\times 10^{23}$ molecules of chloral hydrate has 165.5 g mass of chloral hydrate

So, 500 molecules of chloral hydrate has $\frac{6.022\times 10^{23}}{500}\times 165.5=1.99\times 10^{23}$ mass of chloral hydrate

The mass of exactly 500 molecules of chloral hydrate is, $1.99\times 10^{23}$

3 0

3 years ago

Under certain conditions the rate of this reaction is zero order in dinitrogen monoxide with a rate constant of ·0.0047Ms−1: 2N2

leva [86]

Answer:

250 mmol are left after 26.60 secs ≅ 26.6 seconds

Explanation:

zero order kinetics formula is:

[A] = [A₀] - kt

where [A] = amount left; [A₀] = amount remaining; k = rate constant; t = time

concentration [A₀] = mole/volume = 0.5 mole/2.0L = 0.25

[A] = 0.25 mole/2.0L = 0.125 M

k = 0.0047 Ms⁻¹

t = {[A]-[A₀]}/-k = (0.125 - 0.25)/(-0.0047) = 26.60 seconds = 26.6 seconds

the amount is reduced by half after 26.6 seconds

6 0

3 years ago

Determine the amount of both hydrogen and oxygen in a 500mL sample of Water.

alina1380 [7]

There would be about 1.67 x 10^25 oxygen atoms and about 3.34 x 10^25 hydrogen atoms.

3 0

3 years ago

Why do you not fill you car tires with just oxygen?

Digiron [165]

Answer:

in text

Explanation:

But the main reason for using pure nitrogen is resistance to leakage. Nitrogen molecules find it harder to sneak out through the tire past the rubber molecules than oxygen molecules. This makes nitrogen a good bet for race car, aircraft and heavy-duty equipment where precise or constant pressure is critical.

BRAINLIEST PLEASE !!!!

8 0

3 years ago