How many units is the perimeter of a rectangle with vertices located at (-3,2), (-3,3),(3,3), and (3,-2)?
1 answer:
The perimeter of the rectangle with vertices (-3,2), (-3,3),(3,3), and (3,-2) is 19.21 units.
<h3>What is a distance formula?</h3>It is defined as the formula for finding the distance between two points. It has given the shortest path distance between two points.
The distance formula can be given as:
We have:
Vertices of the rectangle:
(-3,2), (-3,3), (3,3), and (3,-2)
The distance between (-3, 2) and (-3, 3):
= 1
The distance between (-3, 3) and (3, 3):
= 6
The distance between (3, 3) and (3, -2):
= 5
The distance between (3, -2) and (-3, 2):
= 7.21
Perimeter of the rectangle = 1 + 6 + 5 + 7.21 = 19.21 units
Thus, the perimeter of the rectangle with vertices (-3,2), (-3,3), (3,3), and (3,-2) is 19.21 units.
Learn more about the distance formula here:
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A vector given in component form is presented as <x, y>, where <em>x</em> represent the horizontal displacement and <em>y</em> represents the vertical displacement
<u>The </u><u>vector </u><u>that </u><u>maps </u><u>the figure ABCD to its </u><u>image </u>A'B'C'D' is <u><3, -7></u>
The reason the above value is correct is as follows:
The coordinates of the vertices of the preimage ABCD are A(-6, 4), B(-1, 4), C(3, 1), and D(-5, 1)
The coordinates of the vertices of the image A'B'C'D' are A'(-3, -3), B'(2, -3), C'(6, -6), and D'(-2, -6)
The component form of the vector that maps the figure to its image is given as follows;
Therefore,
The component form of the vector that maps the figure ABCD to its image A'B'C'D' is <3, -7>
Learn more about the component form of a vector here: