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trasher [3.6K]
2 years ago
10

How many units is the perimeter of a rectangle with vertices located at (-3,2), (-3,3),(3,3), and (3,-2)?

Mathematics
1 answer:
ArbitrLikvidat [17]2 years ago
7 0

The perimeter of the rectangle with vertices (-3,2), (-3,3),(3,3), and (3,-2) is 19.21 units.

<h3>What is a distance formula?</h3>

It is defined as the formula for finding the distance between two points. It has given the shortest path distance between two points.

The distance formula can be given as:

\rm d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have:

Vertices of the rectangle:

(-3,2), (-3,3), (3,3), and (3,-2)

The distance between (-3, 2) and (-3, 3):

= 1

The distance between (-3, 3) and (3, 3):

= 6

The distance between (3, 3) and  (3, -2):

= 5

The distance between (3, -2) and (-3, 2):

= 7.21

Perimeter of the rectangle = 1 + 6 + 5 + 7.21 = 19.21 units

Thus, the perimeter of the rectangle with vertices (-3,2), (-3,3), (3,3), and (3,-2) is 19.21 units.

Learn more about the distance formula here:

brainly.com/question/18296211

#SPJ1

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