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3 years ago

Find (a) PQ to the nearest tenth and (b) the coordinates of the midpoint of __ pq.

Mathematics

1 answer:

lutik1710 [3]3 years ago

4 0

Answer:

a) 5units

b) (4.5, 4)

Step-by-step explanation:

Let the coordinate of P and Q be P(3, 2) and Q(6, 6)

PQ can be gotten using the distance formula;

PQ =√(6-2)²+(6-3)²

PQ = √4²+3²

PQ =√16+9

PQ =√25

PQ = 5units

Midpoint M is expressed as;

M(X, Y) = {(x1+x2)/2, y1+y2/2}

X = x1+x2/2

X = 3+6/2

X= 9/2

X = 4.5

Similarly;

Y = y1+y2/2

Y = 2+6/2

Y = 8/2

Y = 4

Hence the midpoint of PQ is (4.5, 4)

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Answer:

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Step-by-step explanation:

Given

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Required

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Start by differentiating P w.r.t t

Using first principle:

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Where

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So, we have:

$t = \frac{-(-48) \± \sqrt{(-48)^2 - 4*3*20}}{2*3}$

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Split:

$t = \frac{48 + \45.4}{6}$ or $t = \frac{48 - \45.4}{6}$

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Approximate to whole numbers

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Find ​(a) PQ to the nearest tenth and ​(b) the coordinates of the midpoint of __ pq.

Find (a) PQ to the nearest tenth and (b) the coordinates of the midpoint of __ pq.