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Anestetic [448]

3 years ago

6

Tom works part-time at a theme park. last week he worked the following hours but he needs to complete his timesheet in decimals.

tom earned £173 last week and he worked for 25 hours. how much does he earn per hour?

2 answers:

svetoff [14.1K]3 years ago

8 0

He earns 6.92 per hour

iogann1982 [59]3 years ago

4 0

173/25= $6.92 per hour

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The vaue of x is 23 cm

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Un avion sale de Córdoba con destino a Estados Unidos realiza escalas en Chile y en Bolivia la capacidad del avión es de 507 pas

Dahasolnce [82]

Answer:

386 passengers arrive at Estados Unidos.

386 pasajeros aterrizará en Estados Unidos.

Step-by-step explanation:

English Translation

A plane from Córdoba bound for Estados Unidos and makes stops in Chile and Bolivia. The plane has a capacity for 507 passengers. He leaves the Córdoba airport with 119 empty seats. In Chile 33 passengers go down and 121 go up. In Bolivia 129 go down and 39 go up. How many arrive in Estados Unidos?

- The plane has capacity for 507 passengers.

- 119 seats are empty when it leaves Córdoba.

Meaning that there were (507 - 119) passengers on board = 388 passengers

- In Chile 33 passengers go down and 121 go up.

Number of passenger become

388 - 33 + 121 = 476 passengers

- In Bolivia 129 go down and 39 go up.

Number of passengers become

476 - 129 + 39 = 386 passengers.

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2 years ago

URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(c) $\log_2(\dfrac{64}{8})=3$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

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What the 15th sequence for 4.5n-8

damaskus [11]

Given:
The sequence formula;
Tn = 4.5n - 8 (Where n = term number)

Required:
15th term = ?

Procedure:
All you need to do is use n = 15

T15 = 4.5(15) - 8
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Conclusion:
The 15th term of the sequence is 59.5.

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