Answer:
The answer is below
Step-by-step explanation:
Let S denote syntax errors and L denote logic errors.
Given that P(S) = 36% = 0.36, P(L) = 47% = 0.47, P(S ∪ L) = 56% = 0.56
a) The probability a program contains both error types = P(S ∩ L)
The probability that the programs contains only syntax error = P(S ∩ L') = P(S ∪ L) - P(L) = 56% - 47% = 9%
The probability that the programs contains only logic error = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
P(S ∩ L) = P(S ∪ L) - [P(S ∩ L') + P(S' ∩ L)] =56% - (9% + 20%) = 56% - 29% = 27%
b) Probability a program contains neither error type= P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
c) The probability a program has logic errors, but not syntax errors = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
d) The probability a program either has no syntax errors or has no logic errors = P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
Answer:
D) six hundred twenty-nine thousandths > six times one tenth plus three times one hundredth plus two times one thousandth
629000>8403 TRUE
Step-by-step explanation:
A) six times one tenth plus three times one hundredth plus two times one thousandth < six hundred twenty-nine thousandths
8,403.00
<629000 FALSE
B) six times one tenth plus three times one hundredth plus two times one thousandth = six hundred twenty-nine thousandths
8403= 629000 FALSE
C) six hundred twenty-nine thousandths < six times one tenth plus three times one hundredth plus two times one thousandth
629000<8403 FALSE
D) six hundred twenty-nine thousandths > six times one tenth plus three times one hundredth plus two times one thousandth
629000>8403 TRUE
Hope This Helps!!!
Your deck is bigger because it’s 3 and 2/3 and your neighbor is 3 and 8/9 your deck is bigger because 2/3 are bigger then 8/9
percent increase = (new -original)/original
= (1200-550)/550
650/550
=1 100/550
1 2/11
1.181818
118.18 percent
to the nearest whole number
118 %
<span>A 96% confidence interval means that 96% of the time you can believe that the result will fall into a range of numbers. In the case of weight lifting this would mean that 96% of the time, the proportion of weight-lifting injuries were accidental would fall in between the two parameters set forth.</span>
