Question

A slow pitch softball diamond is actually a square 60 ft on a side. how far is it from home to second ​base?

Answer 1

For this case we have a square whose sides are known and equal to 60 ft.
 We want to find the diagonal of the square.
 For this, we use the Pythagorean theorem.
 We have then:
 $d^2 = 60^2 + 60^2 d = \sqrt{60^2 + 60^2} d = \sqrt{3600 + 3600} d = \sqrt{2*3600} d = 60\sqrt{2}$
 Answer:
 from home to second ​base it is about:
 $d = 60\sqrt{2} feet$