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Gemiola [76]
3 years ago
5

PLEASE HELP DUE IN 5 MIN

Mathematics
1 answer:
Verdich [7]3 years ago
4 0
The answer to this question is you do 16 and take half of that and that will be your other sides
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3/2 (6 - 18x) &gt; 12<br> Solve
Ivanshal [37]

Answer:

x is less than 1/9

Step-by-step explanation:

Distribute the 3/2 to the (6-18x), which gives you 9-27x is greater than 12. Subtract the 9 over, which gives you -27x is greater than 3. Divide both sides by -27, but when you divide by a negative, you have to flip the sign, so finally, you get x is less than 1/9.

8 0
3 years ago
What is the slope of a line that is parallel to the x-axis?
JulijaS [17]
The gradient of x axis is zero. As such, the gradient of the line parallel to x-axis can only be zero
3 0
3 years ago
The measure of the two angles in a triangle are shown in the diagram Which equation can be used to find the value of x?
Gnesinka [82]

Answer:

48+2x=180

Step-by-step explanation:

This is an isosceles triangle, this means that two of the sides/angles are the same. I'm not 100% sure if I'm right though.

4 0
3 years ago
Read 2 more answers
The distributions of X and of Y are described here. If X and Y are independent, determine the joint probability distribution of
max2010maxim [7]

Answer:

The joint probability distribution of X and Y is shown below.

Step-by-step explanation:

The distributions of X and of Y are described as follows:

    X :    0           1

P (X) : 0.23      0.77

     Y :    1            2          3

P (Y) : 0.40     0.22     0.38

It is provided that X and Y are independent.

That is:

P (X ∩ Y) = P (X) × P (Y)

Compute the joint probability distribution of X and Y as follows:

P(X=0,Y=1)=P(X=0)\times P(Y=1)=0.23\times 0.40=0.92\\\\P(X=0,Y=2)=P(X=0)\times P(Y=2)=0.23\times 0.22=0.0506\\\\P(X=0,Y=3)=P(X=0)\times P(Y=3)=0.23\times 0.38=0.0874\\\\P(X=1,Y=1)=P(X=1)\times P(Y=1)=0.77\times 0.40=0.308\\\\P(X=1,Y=2)=P(X=1)\times P(Y=2)=0.77\times 0.22=0.1694\\\\P(X=1,Y=3)=P(X=1)\times P(Y=3)=0.77\times 0.38=0.2926

      X       0                  1

<u>Y                                              </u>

1           0.9200        0.3080

2          0.0506        0.1694

3          0.0874         0.2926

6 0
3 years ago
A sand volleyball court has an area of 162 square meters and a perimeter of 54 meters. What are the dimensions of the volleyball
tresset_1 [31]
I honestly dont know how to figure this one out.
3 0
3 years ago
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