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Darina [25.2K]
1 year ago
7

What are the zeros of the function f(x) = x^4 - x² - 2?

Mathematics
1 answer:
vaieri [72.5K]1 year ago
7 0

Answer:

x= i\\\\ x = -i \\\\x=\sqrt 2\\\\x = -\sqrt 2

Step-by-step explanation:

~~~~~~x^4 -x^2 -2=0\\\\\implies x^2 \cdot x^2-2x^2 +x^2 -2 = 0\\\\\implies x^2(x^2 -2) +(x^2 -2) =0\\\\\implies (x^2 +1)(x^2 -2) = 0\\\\ \implies x^2 +1=0~~~~~~~~\text{or}~~~~~~~~~x^2 -2 = 0\\\\ \implies x = \pm\sqrt{-1}~~~~~~~\text{or}~~~~~~~~~~ x = \pm\sqrt 2\\\\\implies x= \pm i~~~~~~~~~~~~~\text{or}~~~~~~~~~ x= \pm\sqrt 2

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Find the distance of the line segment joining the two points (-4 /2 - /12) and (/32, 2/3)
astraxan [27]

Answer: 4\sqrt{3} .

Step-by-step explanation:

Distance formula : Distance between points (a,b) and (c,d) is given by :-

D=\sqrt{(d-b)^2+(b-a)^2}

Distance between points (-4\sqrt{2},\sqrt{12}) \text{ and }(-\sqrt{32}, 2\sqrt{3}).

D=\sqrt{(2\sqrt{3}-(-\sqrt{12}))^2+(-\sqrt{32}-(-4\sqrt{2}))}\\\\=\sqrt{(2\sqrt{3}+\sqrt{2\times2\times3})^2+(-\sqrt{4\times4\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}-\sqrt{2^2\times3})^2+(-\sqrt{4^2\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}+2\sqrt{3})^2+(-4\sqrt{2}+4\sqrt{2})^2}\\\\=\sqrt{(4\sqrt{3})^2+0}\\\\=4\sqrt{3}\text{ units}

Hence, the correct option is 4\sqrt{3} .

3 0
3 years ago
5-4x-8y How many TERMS are present in this expression? 2. How many TERMS are present in this expression? List them: List them: I
Sphinxa [80]

Answer:

2 terms the terms are x and y

7 0
2 years ago
Read 2 more answers
Draw an example of a composite figure that has a volume between 750 cubic inches and 900 cubic inches
grigory [225]

Volume:

V \approx 888.02in^3 \\ \\ And, \ 750in^3

<h2>Explanation:</h2>

A composite figure is formed by two or more basic figures or shapes. In this problem, we have a composite figure formed by a cylinder and a hemisphere as shown in the figure below, so the volume of this shape as a whole is the sum of the volume of the cylinder and the hemisphere:

V_{total}=V_{cylinder}+V_{hemisphere} \\ \\ \\ V_{total}=V \\ \\ V_{cylinder}=V_{c} \\ \\ V_{hemisphere}=V_{h}

So:

V_{c}=\pi r^2h \\ \\ r:radius \\ \\ h:height

From the figure the radius of the hemisphere is the same radius of the cylinder and equals:

r=\frac{8}{2}=4in

And the height of the cylinder is:

h=15in

So:

V_{c}=\pi r^2h \\ \\ V_{c}=\pi (4)^2(15) \\ \\ V_{c}=240\pi in^3

The volume of a hemisphere is half the volume of a sphere, hence:

V_{h}=\frac{1}{2}\left(\frac{4}{3} \pi r^3\right) \\ \\ V_{h}=\frac{1}{2}\left(\frac{4}{3} \pi (4)^3\right) \\ \\ V_{h}=\frac{128}{3}\pi in^3

Finally, the volume of the composite figure is:

V=240\pi+\frac{128}{3}\pi \\ \\ V=\frac{848}{3}\pi in^3 \\ \\ \\ V \approx 888.02in^3 \\ \\ And, \ 750in^3

<h2>Learn more:</h2>

Volume of cone: brainly.com/question/4383003

#LearnWithBrainly

4 0
3 years ago
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aliina [53]
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5 0
3 years ago
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pshichka [43]

Answer:

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Step-by-step explanation:

Monday - 3.11

Tuesday - 0.81

Wednesday - 0.81 x 2= 1.62

3.11 + 0.81 + 1.62=5.54 inches

4 0
2 years ago
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