Answers for the 2 boxes please :)
2 answers:
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Given:
Consider the completer question is "If ∆BTS≅∆GHD, BS=25, TS=14, BT=31, GD=4x-11, m∠S=56, m∠B=21 and m∠H=(7y+5), find the values of x and y.
To find:
The values of x and y.
Solution:
We have,
(Given)
(CPCTC)
Divide both sides by 4.
In ∆BTS,
(Angle sum property)
Now,
(CPCTC)
Divide both sides by 7.
Therefore, the value of x is 9 and value of y is 14.