If y = x + 5 and y = 11, then x = what?

A square matrix A is said to be idempotent iff A2 = A. (i) Show that if A is idempotent, then so is I − A. (ii) Show that if A i

muminat

Answer:

Step-by-step explanation:

Given that A is a square matrix and A is idempotent

$A^2 = A$

Consider I-A

i) $(I-A)^2 = (I-A).(I-A)\\= I^2 -2A.I+A^2\\= I-2A+A\\=I-A$

It follows that I-A is also idempotent

ii) Consider the matrix 2A-I

$(2A-I).(2A-I)=\\4A^2-4AI+I^2\\= 4A-4A+I\\=I$

So it follows that 2A-I matrix is its own inverse.

7 0

3 years ago

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let X = number of vehicles that pass the inspection.

The probability of the random variable X is P (X) = 0.70.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

$=(0.70)^{3}\\=0.343$

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

$=1-0.343\\=0.657$

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

= P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

+ P (Only 3rd vehicle passes)

$=(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189$

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

+ P (0 vehicles passes)

$=0.189+(0.30\times0.30\times0.30)\\=0.216$

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let X = all 3 vehicle passes and Y = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

$P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525$

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0

3 years ago

1. To go bowling, it costs $2.00 to rent shoes and $3.50 per game. The function t(x) = 3.5x + 2 is used to find the total cost,

borishaifa [10]

Answer:

a. $5.5 b. $19.5

Step-by-step explanation:

t(x)=3.5x+2

x = amount of games

a. t(1)=3.5(1)+2

t(1)=3.5+2

t(1)=5.5

b. t(5)=3.5(5)+2

t(5)=17.5+2

t(5)=19.5

4 0

3 years ago

Jeffery and carrie deposit 800.00 into an savings account which earns 4%interest compounded quarterly they want to use the money

tekilochka [14]

Answer:

866.29

Step-by-step explanation:

Deposit = 800
Interest rate = 4% compounded quarterly
Time = 2 years

Number of compounds:

2 / 1/4 = 8

Saving amount at the end of 2 years:

800*(1 + 0.04/4)^8 = 866.29

3 0

3 years ago

C=5/9(F-32) solving for f

Nina [5.8K]

Solve for f
by simplifying both sides of the equation, then isolating the variable.
f=32+9c / 5

5 0

3 years ago