Answer:
2 (real) solutions.
Step-by-step explanation:
A quadratic always has two solutions, whether they are real or complex.
Sometimes the solution is complex, involving complex numbers (2 complex), sometimes they are real and distinct (2 real), and sometimes they are real and coincident (still two real, but they are the same).
In the case of
x^2+3x = 3, or
x² + 3x -3 = 0
we apply the quadratic formula to get
x = (-3 +/- sqrt(3^2+4(1)(3))/2
to give the two solutions
{(sqrt(21)-3)/2, -(sqrt(21)+3)/2,}
both of which are real.
Answer:
Probability of both even is 12×12=14. Given they are both even there are 3 possible even numbers: 2,4,6.
Step-by-step explanation:
Answer:
132.4
Step-by-step explanation:
What are we supposed to be basing this off of? is there no additional information?
A function is odd if:
f ( - x ) = - f ( x )
A ) f ( - x )= 0.8 ( - x ) ^3 = - 0.8 x^3 = - f ( x )
Answer: A ) f ( x ) = 0.8 x^3 is an odd function.
Functions B ) and C ) are even and D) is neither even nor odd.
