Question

What is the area of the figure? 40 ft2 84 ft2 96 ft2 can't be determined

Answer 1

Answer:

$A=80\ ft^2$

Step-by-step explanation:

we know that

The area of the figure is equal to the area of an isosceles triangle (has two equal sides) plus the area of a rectangle

step 1

Find the area of the triangle

The area of the triangle is equal to

$A=\frac{1}{2}bh$

we have

$b=16\ ft$

To find out the height of the triangle Apply the Pythagorean Theorem

$10^2=(16/2)^2+h^2$

solve for h

$100=64+h^2$

$h^2=100-64$

$h^2=36$

$h=6\ ft$

Find the area of triangle

$A=\frac{1}{2}(16)(6)$

$A=48\ ft^2$

step 2

Find the area of rectangle

The area of rectangle is equal to

$A=LW$

we have

$L=16\ ft\\W=2\ ft$

substitute

$A=(16)(2)=32\ ft^2$

step 3

Find the area of the figure

Adds the areas

$A=48+32=80\ ft^2$