Answer:
The answer is below
Explanation:
The amount of power dissipated by a processor is given by the formula:
P = fCV²
Where f = clock rate, C = capacitance and V = Voltage
For the old version of processor with a clock rate of f, capacitance C and voltage of V, the power dissipated is:
P(old) = fCV²
For the new version of processor with a clock rate of 20% increase = (100% + 20%)f = 1.2f, capacitance is the same = C and voltage of 20% increase = 1.2V, the power dissipated is:
P(new) = 1.2f × C × (1.2V)² = 1.2f × C × 1.44V² =1.728fCV² = 1.728 × Power dissipated by old processor
Hence, the new processor is 1.728 times (72.8% more) the power of the old processor
Answer:
A and C
Explanation:
To obtain information about the case of the error the engineer would navigte thus:
Endpoint > Log Files > messages.log > (c) VCS > Maintenance > Diagnostics > Incident Reporting > View.
Cheers
Answer:
I believe it is just a task. Since there exists(on windows) the Task Manager application, where you can stop any running <em>task, </em>I think that they are called tasks
Explanation: