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Shalnov [3]
2 years ago
11

A fabric store sells two types of ribbon. One customer buys 3 rolls of the lace ribbon and 2 rolls of the satin ribbon and has a

total of 120 yards of
ribbon. Another customer buys 2 rolls of the lace ribbon and 4 rolls of the satin ribbon and has a total of 160 yards of ribbon.
How many yards are on one roll of lace ribbon and one roll of satin ribbon?
OA. There are 10 yards on one roll of lace ribbon and there are 40 yards on one roll of satin ribbon.
OB. There are 20 yards on one roll of lace ribbon and there are 30 yards on one roll of satin ribbon.
OC. There are 30 yards on one roll of lace ribbon and there are 20 yards on one roll of satin ribbon.
OD. There are 40 yards on one roll of lace ribbon and there are 10 yards on one roll of satin ribbon.
Mathematics
2 answers:
Aleksandr [31]2 years ago
7 0

Answer:

B

Step-by-step explanation:

3(20)=60

2(30)=60

60+60=120

2(20)= 40

4(30)= 120

40+120=160

Citrus2011 [14]2 years ago
5 0

Answer:

20 yards in the lace ribbon and there are 30 yards on one roll of satin ribbon

Step-by-step explanation:

3x + 2y = 120   (1)

   2x + 4y = 160   (2)

Divide eq(2) by 2 (both sides). Keep equation (1) as is.  You will get

   3x + 2y = 120   (1')

    x + 2y =  80   (2')

Now subtract eq(2') from eq(1').  You will get

   2x = 120 - 80 = 40

    x =  40/2 = 20.

Then from equation (2'),  

   20 + 2y = 80

        2y = 80 - 20 = 60

         y   = 60/2 = 30

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3 years ago
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a car dealer buys a luxury car for $65,200 and sells it for 85,650. What is the percent increase in the price of the cara car de
nika2105 [10]

Answer:

The percent increase in the price of the car is <u>31.36%</u>.

Step-by-step explanation:

Given:

A car dealer buys a luxury car for $65,200 and sells it for $85,650.  

Now, to find the percent increase in the price of the car.

Cost price of the luxury car = $65,200.

Sell price of the luxury car = $85,650.

So, the price of the car increased by:

Sell price of the luxury car - Cost price of the luxury car.

=\$85,650-\$65,200\\\\=\$20,450.

<em>Thus, the price of car increased by $20,450.</em>

Now,to get the percent increase in the price of the car:

\frac{20450}{65200} \times 100

=0.3136\times 100

=31.36\%.

Therefore, the percent increase in the price of the car is 31.36%.

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This would vary on the perspective of the solver. In this case, the solution would be

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I hope I was able to answer your question. Have a good day.




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