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Anna [14]
3 years ago
12

The sum of three consecutive even integers is 258. write an equation ad solve to find the integers

Mathematics
2 answers:
slavikrds [6]3 years ago
8 0

The consecutive integers are 85,86,87

Explanation:

n

:

the first number

n

+

1

:

the second number

n

+

2

:

the third number

n

+

(

n

+

1

)

+

(

n

+

2

)

=

258

3

n

+

3

=

258

3

n

=

258

−

3

3

n

=

255

n

=

255

3

n

=

85

n

+

1

=

85

+

1

=

86

n

+

2

=

85

+

2

=

87

vodka [1.7K]3 years ago
5 0
Let x, x+2 and x+4 be the three consecutive even integers

from question, we have,
x+x+2+x+4 = 258
=> 3x + 6 = 258
=> 3x = 252
=> x = 252/3
=> x = 84
now,
x+2 = 86
and x+ 4 = 88
therefore the three consecutive even integers are 84, 86 and 88
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Answer:

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Step-by-step explanation:

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8 0
3 years ago
Someone please help.
Alexxandr [17]

Hi there!

f(x)+f(x+1)=4f(x)

There are 3 parts to this equation:

f(x)

f(x+1)

4f(x)

We must first determine these three parts separately.

<u>1) f(x)</u>

We're given that  f(x)=3^x:

⇒ f(x)=3^x:

<u>2) f(x+1)</u>

Now, we must find f(x+1). To do so, add 1 to x in the original function f(x)=3^x:

⇒ f(x+1)=3^x^+^1

<u>3) 4f(x)</u>

To find 4f(x), multiply the original function f(x)=3^x by 4:

4f(x)=4*3^x:

<u>4) Put it all together</u>

Now, plug each of the three parts into the equation f(x)+f(x+1)=4f(x):

f(x)+f(x+1)=4f(x)

3^x+3^x^+^1=4*3^x\\3^x+3^x*3=4*3^x

Factor the left side

3^x*(1+3)=4*3^x

Divide both sides by 3^x

1+3=4\\4=4

Because this equation is true, f(x)+f(x+1)=4f(x) is therefore true.

I hope this helps!

3 0
3 years ago
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