Answer:
the correct answer is option b. root 13
If for the slower printer it takes 10 hours for the whole thing, how much has it done in 1 hour? well, since it takes 10 hours total, in 1 hour it has only done 1/10 th of the whole work.
the faster printer however, can do it in 6 total, how much has it done in 1 hour? well, 1/6 of the whole work.
now, let's say, they both work together, and it takes "t" hours to finish the whole thing with both rolling.
let's add both rates to see how much that is,
which is 3 hours and 45 minutes.
If you count the zeros it’s
one billionth
Answer: (y-c)/m
Reasoning:
Subtract c from both sides [ y-c=mx+c-c ]
Divide m from both sides [ (y-c)/m=mx/m ]
Answer:
Choose some points for x to find its y, the f(x).
To find its inverse, switch the x and y coordinates.
y = 3x + 1
y = 3(-3) + 1
y = -8
f(x) (-3, -8)
f⁻¹(x) (-8, -3)
y = 3x + 1
y = 3(-2) + 1
y = -5
f(x) (-2, -5)
f⁻¹(x) (-5, -2)
y = 3x + 1
y = 3(-1) + 1
y = -2
f(x) (-1, -2)
f⁻¹(x) (-2, -1)
y = 3x + 1
y = 3(0) + 1
y = 1
f(x) (0, 1)
f⁻¹(x) (1, 0)
y = 3x + 1
y = 3(1) + 1
y = 4
f(x) (1, 4)
f⁻¹(x) (4, 1)
y = 3x + 1
y = 3(2) + 1
y = 7
f(x) (2, 7)
f⁻¹(x) (7, 2)
y = 3x + 1
y = 3(3) + 1
y = 10
f(x) (3, 10)
f⁻¹(x) (10, 3)