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Amiraneli [1.4K]
2 years ago
12

How many ways are there to choose a soccer team consisting of 3 forwards, 4 midfield players, and 3 defensive players, if the pl

ayers are chosen from 8 forwards, 6 midfield players and 8 defensive players?
Mathematics
1 answer:
klio [65]2 years ago
7 0

Using the combination formula, it is found that there are 47,040 ways to form a soccer team.

<h3>What is the combination formula?</h3>

Each of the different groups or selections can be formed by taking some or all of a number of objects, irrespective of their arrangments is called a combination.

^mC_k = \dfrac{m!}{k! \times (m-k)!}

A soccer team consisting of 3 forwards, 4 midfield players, and 3 defensive players, if the players are chosen from 8 forwards, 6 midfield players and 8 defensive players

Since they are independent of each other, the total number of combinations will be;

^mC_k = \dfrac{8!}{3! \times (5)!}  \times \dfrac{6!}{4! \times (2)!} \times \dfrac{8!}{3! \times (5)!} \\\\^mC_k =47,040

Hence, There are 47,040 ways to form a soccer team.

More can be learned about the combination at brainly.com/question/25821700

#SPJ1

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Answer:

7 days

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2 years ago
Use the three steps to solve the problem.
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Step-by-step explanation:

Let,

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Keywords: algebraic equation, addition

Learn more about addition at:

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Answer:

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Step-by-step explanation:

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Answer:

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answer up above

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