Question

How many ways are there to choose a soccer team consisting of 3 forwards, 4 midfield players, and 3 defensive players, if the players are chosen from 8 forwards, 6 midfield players and 8 defensive players?

Answer 1

Using the combination formula, it is found that there are 47,040 ways to form a soccer team.

What is the combination formula?

Each of the different groups or selections can be formed by taking some or all of a number of objects, irrespective of their arrangments is called a combination.

$^mC_k = \dfrac{m!}{k! \times (m-k)!}$

A soccer team consisting of 3 forwards, 4 midfield players, and 3 defensive players, if the players are chosen from 8 forwards, 6 midfield players and 8 defensive players

Since they are independent of each other, the total number of combinations will be;

$^mC_k = \dfrac{8!}{3! \times (5)!} \times \dfrac{6!}{4! \times (2)!} \times \dfrac{8!}{3! \times (5)!} \\\\^mC_k =47,040$

Hence, There are 47,040 ways to form a soccer team.

More can be learned about the combination at brainly.com/question/25821700

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