Answer:
Check the explanation
Step-by-step explanation:
Let 
and 
be sample means of white and Jesse denotes are two random variables.
Given that both samples are having normally distributed.
Assume having with mean 
and having mean 
Also we have given the variance is constant
A)
We can test hypothesis as
For this problem
Test statistic is
Where
We have given all information for samples
By calculations we get
s=2.41
T=2.52
Here test statistic is having t-distribution with df=(10+7-2)=15
So p-value is P(t15>2.52)=0.012
Here significance level is 0.05
Since p-value is <0.05 we are rejecting null hypothesis at 95% confidence.
We can conclude that White has significant higher mean than Jesse. This claim we can made at 95% confidence.
Answer:
5
Step-by-step explanation:
9x+6y=-3
9x+6(-8)=-3
9x-48=-3
9x=45
x=5
0.5 because 50 is 1/2 of 100.
For this case we have that the main function is given by:
We apply the following transformations:
Vertical expansions:
To graph y = a * f (x)
If a> 1, the graph of y = f (x) is expanded vertically by a factor a.
For a = 5 we have:
Vertical translations:
Suppose that k> 0
To graph y = f (x) + k, move the graph of k units up.
For k = 5 we have:
Answer:
The graph of g (x) is the graph of f (x) stretched vertically by a factor of 5 and translated up 5 units.
On simplifying, we get
<h2>Therefore, correct option is 1st option.</h2>
