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alekssr [168]
2 years ago
10

Please help i don't understand!

Mathematics
1 answer:
Troyanec [42]2 years ago
8 0

Answer:

Step-by-step explanation:

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Help asap with Arcs! 30 Points
alexira [117]
The answer is 15

these chords are congruent because the radius of the circle are perpendicular to the them
so we can find EF by making an equation:
3x + 5 = x + 35 \\ 3x - x = 35 - 5 \\ 2x = 30 \\ x = \frac{30}{2} = 15

so EF is = 3(15)+5=50
good luck
6 0
3 years ago
X/3 = 2,how to calculate x? <br> please help me
liq [111]

Given:

  • \sf  \dfrac{x}{3}  = 2

Solution:

\longrightarrow \sf \dfrac{x}{3}  = 2 \\  \\  \sf\longrightarrow x = 3 \times 2 \\  \\  \longrightarrow   {\underline{\boxed{ \pink {\sf{x = 6}}} }}\\  \\

4 0
2 years ago
Read 2 more answers
(235) a prime number
Llana [10]

Answer:

235 is not Prime. It’s Composite.

Step-by-step explanation:

Factors of 235:

1, 5, 47, 235.

1 x 235 = 235,

47 x 5 = 235.

Prime Numbers have the number 1 and the number it's self.

This number has 4 factors, which means it’s composite,

Composite Numbers have 3 or more factors.

4 0
2 years ago
A 210-N mass is suspended from a horizontal beam by two cables that make angles of 29 degrees and 53 degrees with the beam. Find
Nonamiya [84]

The tension in both cables are calculated as; T₁ = 127.63 N and T₂ = 185.48 N

<h3>How to find the Tension in Suspended Cables?</h3>

Resolving forces in the y direction gives us;

T₁ sin 29° + T₂ sin 53° = 210  ------(eq 1)

Resolving forces in the horizontal direction gives;

T₁ cos 29° = T₂ cos 53°   ----(eq 2)

T₁ = T₂ cos 53°/cos 29°

Thus;

(T₂ cos 53°/cos 29°)sin 29° + T₂ sin 53° = 210  

0.3336T₂ + 0.7986T₂ = 210

T₂ = 210/1.1322

T₂ = 185.48 N

Thus;

T₁ = 185.48 cos 53°/cos 29°

T₁ = 127.63 N

Read more about Tension in Cables at; brainly.com/question/11653585

#SPJ1

7 0
2 years ago
Mel cleans houses. She earns $7.50 every hour she dusts. She earns $10.00 every hour that
r-ruslan [8.4K]
Scrubbing the floor=15:00$
Dusting=15:00$
Total:30:00$
7 0
2 years ago
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