Each prize for a carnival booth costs $0.32. How many prizes can you buy with $96?
2 answers:
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Answer:
The probability that the plane is oveloaded is P=0.9983.
The pilot should take out the baggage and send it in another plain or have less passengers in the plain to not overload.
Step-by-step explanation:
The aircraft will be overloaded if the mean weight of the passengers is greater than 163 lb.
If the plane is full, we have 41 men in the plane. This is our sample size.
The weights of men are normally distributed with a mean of 180.5 lb and a standard deviation of 38.2.
So the mean of the sample is 180.5 lb (equal to the population mean).
The standard deviation is:
Then, we can calculate the z value for x=163 lb.
The probability that the mean weight of the men in the airplane is below 163 lb is P=0.0017
Then the probability that the plane is oveloaded is P=0.9983:
The pilot should take out the baggage or have less passengers in the plain to not overload.
Answer:
<em>The area of the shaded part = 61.46</em>
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Step-by-step explanation:
Assume the hypotenuse of the triangle is c (c>0)
As the triangle inscribed in the semi circle is the right angle triangle, its hypotenuse is equal to the diameter of the circle.
The hypotenuse of the triangle can be calculated by Pythagoras theorem as following:
=> c = 10
So that the semi circle has the diameter = 10 => its radius = 5
- The total area of 2 semi circles is equal to the area of the circle with radius =5
=> The total area of 2 semi circles is: x
= 25
- The area of a triangle inscribed in the semi circle is: 1/2 x a x b = 1/2 x
x
= 20
=> The area of 2 triangles inscribed in 2 semi circles is: 2 x 20 = 40
- The area of the square is:
=
It can be seen that:
<em>The area of the shaded part = The area of the square - The total area of 2 semi circles + The total are of 2 triangles inscribed in semi circles </em>
<em>= 100 - 25</em><em> + 40 = 61.46</em>