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Answer:
The correct option is (b).
Step-by-step explanation:
If X N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variate is known as the standard normal distribution.
The mean and standard deviation of the active minutes of students is:
<em>μ</em> = 60 minutes
<em>σ </em> = 12 minutes
Compute the <em>z</em>-score for the student being active 48 minutes as follows:
Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.
The correct option is (b).
The answer is 8884.37 times<span>
In many cases, B is approximately proportional to the three-quarters power of M:
</span>
<span>
Elephant:
M1 = 4.6 mt = 4.6 * 1,000,000 g = 4,600,000 g
</span>
<span>
Mouse
</span>M2 = 25 g
<span>determine how many times greater the metabolic rate of an elephant is than that of a mouse:
B1/B2 = </span>99327.24 / 11.18 = 8884.37 times
In many cases, B is approximately proportional to the three-quarters power of M:
</span>
<span>
Elephant:
M1 = 4.6 mt = 4.6 * 1,000,000 g = 4,600,000 g
</span>
<span>
Mouse
</span>M2 = 25 g
<span>determine how many times greater the metabolic rate of an elephant is than that of a mouse:
B1/B2 = </span>99327.24 / 11.18 = 8884.37 times