Plug in 6 for everywhere s is in the equation
r = 9 + 3s
r = 9 + 3(6)
r = 9 + 18
r = 27
27 is the answer!
You would move over the -2 making the equation look like this 4x>3x+7. Then move the 3x to the other side of the equation making it look like this 1x>7. Thus the answer is x>7.
The unit rate you're trying to find is pages per day(or p/d), so the equation needs to have both a unit for pages and for days.
The equation we have is:

If they read 5,249 <em>pages</em>, then we can include the unit for pages in the equation.
Since we also know that <em>d</em> is the number of days it took, you can replace <em>d</em> with days.
The equation becomes:

Now that we have one variable, we can solve for <em>p/d</em>:

Thus it took them 181 days to read it all.
If Johnny read 5,249 pages over 181 days and the unit rate is pages per day(p/d), then the equation for finding <em>p/d</em> is:
Johnny read 29 pages per day.
Answer:
μ ≈ 2.33
σ ≈ 1.25
Step-by-step explanation:
Each person has equal probability of ⅓.
![\left[\begin{array}{cc}X&P(X)\\1&\frac{1}{3}\\2&\frac{1}{3}\\4&\frac{1}{3}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7DX%26P%28X%29%5C%5C1%26%5Cfrac%7B1%7D%7B3%7D%5C%5C2%26%5Cfrac%7B1%7D%7B3%7D%5C%5C4%26%5Cfrac%7B1%7D%7B3%7D%5Cend%7Barray%7D%5Cright%5D)
The mean is the expected value:
μ = E(X) = ∑ X P(X)
μ = (1) (⅓) + (2) (⅓) + (4) (⅓)
μ = ⁷/₃
The standard deviation is:
σ² = ∑ (X−μ)² P(X)
σ² = (1 − ⁷/₃)² (⅓) + (2 − ⁷/₃)² (⅓) + (4 − ⁷/₃)² (⅓)
σ² = ¹⁴/₉
σ ≈ 1.25