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<h3>
What is a best practice that can prevent viruses and other malicious code?</h3>
- View email in plain text and don't view email in Preview Pane.
- Using antivirus software is the best way to defend your computer against malicious code.
- If you think your computer is infected, run your antivirus software program. Ideally, your antivirus program will identify any malicious code on your computer and quarantine them so they no longer affect your system
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Answer:
Microsoft Excel and Microsoft word are the part of the MicrosoftOffice Package of productvity software.
I would say B would be the best answer choice out of the given choices
The answer is: [B]: " 2 " .
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Explanation:
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Given the chemical equation:
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<u> ? </u> H₂ + O₂ → 2 H₂<span>O ;
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</span> → <span> We are asked, "What coefficient, if any — should be put in front of the: " H</span>₂ " ;
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(which is on the "left-hand side" side of the chemical equation given— the "reactants") ;
→ to get a balanced chemical equation?
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→ Let us examine the "right-hand side" of this chemical equation—the product(s). In this case, the "product" given is: " 2 H₂O " .
So, on the "right hand side", we have:
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1) 4 "H's" → {Two "H₂" 's = 2 * 2 = "4 H's"} ; <u><em>and</em></u>:
2) 2 "O's" → { Two "O's").
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So, the left-hand side should have:
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1) 4 "H's" ; <u><em>and</em></u>:
2) 2 "O's" ;
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Let us examine the left-hand side (the "reactants").
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" <u> ? </u><u /> H₂ + O₂ " ;
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On the left-hand side, we already have:
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1) " 2 O's " ; → one "O₂" = "2 O's" ; and:
2) "2 H's " ; → one "H<span>₂" .</span>
Now, we would need:
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A "<u>total of "4 H's</u>". Is there any number we could put as a coefficient on the other reactant, which happens to be: "H₂" ; to make a <u><em>total of</em></u> "4 H's" ?
{Note: There are only these TWO (2) reactants in this chemical equation.}.
→ The "H₂" ; as it stands alone, is insufficient—since that would be only "2 H's".
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→ Thus, we can rule out: "Answer choices: [A] and [D]."
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<u>Note</u>:
→ Choice [A]: "1" ; The coefficient, "1"; is generally not (never?) used; and basically would function as the same as:
→ Choice: [D]: "<span>no coefficient is needed".
</span>→ <span>Choices [A] & [D]: would leave us with only "2 H's" on the "reactants side" (i.e. "left-hand side of the equation"; and we need FOUR ("4 H's").
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Since we are given: "H</span>₂" ; what coefficient could we put in front of this to get: "4 H's" ? (4÷2 =2). So we could put a "2" in front of the "H₂" ; to get:
"4 H's". The coefficient, "2" , corresponds directly with:
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→ Answer choice: [B]: "2" .
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{ <u>NOTE</u>: The remaining answer choice, [C], which is, "3" ; is INCORRECT; since 3 "H₂'s" would be "6 H's" ; (since 3 * "2 H's" equal "6 H's") ; which is too many "H's" → We need <u>exactly</u> "4 H's".}.
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So, the correctly balanced equation is:
2 H₂ + O₂ → 2 H₂O ;
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→ The coefficient that goes before the "H₂" ; to make this chemical equation balanced, is: "2" .
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The correct answer is: [B]: "2" .
→ The coefficient that goes before the "H₂" is: "2" .
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Hope this answer—and {lengthy} explanation—is of help!
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