The probability that both the first digit and the last digit of the three-digit number are even numbers will be 0.4 or 40%.
<h3>What is probability?</h3>
Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.
The number of three-digit numbers with distinct digits can be formed using the digits 1, 2, 3, 5, 8, and 9.
Then the probability that both the first digit and the last digit of the three-digit number are even numbers will be
Total event = ⁶C₃ = 20
Favorable event = 8 {218, 238, 258, 298, 812, 832, 852, 892}
Then we have
P = 8/20
P = 0.4
P = 40%
More about the probability link is given below.
brainly.com/question/795909
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