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3 years ago

Which relationship describes angles 1 and 2?

Mathematics

2 answers:

VashaNatasha [74]3 years ago

5 0

Its complementary because they add up to be 90 degrees

Vladimir79 [104]3 years ago

4 0

They are both adjacent and complementary.

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HELP Me NOW NOW NOW NOW

german

Answer:

The answer is 9/16.

Step-by-step explanation:

Using Indices Law,

${( \frac{a}{b}) }^{n} ⇒ \frac{ {a}^{n} }{ {b}^{n} }$

So for this question :

${ (\frac{3}{4}) }^{2}$

$= \frac{ {3}^{2} }{ {4}^{2} }$

$= \frac{3 \times 3}{4 \times 4}$

$= \frac{9}{16}$

7 0

3 years ago

46÷6=? R ? What is the remainder for 46÷6= All i'm asking for is just the remainder.

Rom4ik [11]

Answer:

7.66666666667

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

in a survey of 3271 adults aged 57 through 85 years, it was found that 88.7% of them used at least one prescribed medication

mixer [17]

How many of the 3271 subjects used at least one prescription medication? Round to the nearest integer asneeded.)

Answer:

2902

Step-by-step explanation:

Let the total number of adults within the mentioned age bracket be n=3271

The proportion of adults who used at least one prescription medication be p=88.7%=0.887

The point estimate of population is given by

$p=\frac {x}{n}$ where x is number of individuals in the sample with the specified characteristics and n is the sample size.

Let x be the adults who used at least one prescription medication

$0.887=\frac {x}{3271}$

$x=3271*0.887=2901.377\approx 2902$

3 0

3 years ago

1. Triangle ABC with coordinate points A(-2,3); B(-1,0); C(5,-4) is rotated 90 degrees clockwise. What

Reil [10]

Answer: A'(3,2), B'(0,1) and C'(-4, -5).

Step-by-step explanation:

When we rotate (a,b) 90 degrees clockwise, the new point will be (b,-a).

i.e. rotation rule for 90 degrees clockwise : (x,y) → (y,-x)

Given: Triangle ABC with coordinate points A(-2,3); B(-1,0); C(5,-4) is rotated 90 degrees clockwise.

Then, the new image points for triangle A'B'C' will be :

A(-2,3) → A'(3,-(-2)) =A'(3,2)

B(-1,0)→ B'(0,-(-1)) = B'(0,1)

C(5,-4) → C'(-4, -5)

Hence, the new image points for triangle A'B'C' are A'(3,2), B'(0,1) and C'(-4, -5).

6 0

3 years ago

Transversals angles

sammy [17]

B. 2 because it is inside and on the same side as 1

7 0

3 years ago