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Bess [88]
1 year ago
6

Help me now !! help help help

Mathematics
1 answer:
Fed [463]1 year ago
4 0

Answer:

Step-by-step explanation:

1) Parallelepiped

<em>We need to find its surface area minus the area of the base and the base of the cylinder above.</em>

<em>2 (9) (2.4) = </em><em>43.2</em>

<em>2 (5) (2.4) = </em><em>24</em>

<em>4pi = Area of the base of the cylinder</em>

<em>45 - 4pi </em><em>= Area of the base of the parallelepiped minus covered region.</em>

<em>Surface needed = </em><em>112.2 - 4pi</em>

<em />

<em>2) Cylinder</em>

<em />

<em>We need to find its surface area minus the area of the base.</em>

<em>2 (pi) (2) (3) = 12pi </em>

<em>pi (4) = 4pi</em>

<em>Surface needed = </em><em>16pi</em>

<em></em>

<em>Total surafec needed:  </em>(112.2 - 4pi) + 16pi = 112.2 + 12pi

(This is solved in 'pi' terms)

If this helped, I'd like to have a brainliest. Have a nice day!!

<em />

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