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2 years ago

Which value of P and Q result in an equation with no solutions Qx+12=13x+P

1 answer:

6 0

When you have a question that comes to no solution that means when you went to solve the problem they canceled out to 0.

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Cheyenne took out a 30-year loan for $350,000 at 2.9% interest, compounded monthly. If her monthly payment on the loan will rema

Leto [7]

The answer is d.

Explanation:

1456.80 per month
1456.80 times 12 = how much per year
17481.6 = how much per year
17481.6 times 30 years = 524448
$524448 - the original loan(350,000) = $174,448

6 0

3 years ago

Read 2 more answers

A farmer plants apple trees on a on a 235-acre farm. There are 47,000 apple trees evenly dispersed throughout the farm. How many

Musya8 [376]

Answer:

There are 200 trees per acre.

Step-by-step explanation:

47000 trees divided by 235 acres gets you 200 trees per acre.

When you go back and check your work, 200 trees per acre times 235 acres equals 47000 trees.

I hope this helps! :)

8 0

2 years ago

Instructions: state what additional information is required in order to know that the triangle in the image below are congruent

Dafna1 [17]

Answer:

QP ≈ HG

Common side between those angles are QP and HG

so, they should be congruent to prove AAS

Answered by GAUTHMATH

8 0

2 years ago

What is -4(7x+5)=-160

puteri [66]

Answer is -23

Add 4 from both sides

Subtract 5 from both sides

Then divide 7

6 0

2 years ago

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In a random sample of 45 newborn babies, what is the probability that 40% or fewer of the sample are boys. (Use 3 decimal places

erastova [34]

Answer:

$z= \frac{p- \mu_p}{\sigma_p}$

And the z score for 0.4 is

$z = \frac{0.4-0.4}{\sigma_p} = 0$

And then the probability desired would be:

$P(p$

Step-by-step explanation:

The normal approximation for this case is satisfied since the value for p is near to 0.5 and the sample size is large enough, and we have:

$np = 45*0.4= 18 >10$

$n(1-p) = 45*0.6= 27 >10$

For this case we can assume that the population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Where:

$\mu_{p}= \hat p = 0.4$

$\sigma_p = \sqrt{\frac{p(1-p)}(n} =\sqrt{\frac{0.4(1-0.4)}(45}= 0.0703$

And we want to find this probability:

$P(p$

And we can use the z score formula given by:

$z= \frac{p- \mu_p}{\sigma_p}$

And the z score for 0.4 is

$z = \frac{0.4-0.4}{\sigma_p} = 0$

And then the probability desired would be:

$P(p$

7 0

3 years ago

Read 2 more answers