Answer:
the height when the plant was planted
Step-by-step explanation:
The "y-intercept" is the value of the dependent variable (height) when the independent variable (days) has a value of zero.
The table description tells you the table represents height since the plant was planted. If days since the plant was planted are zero, the height at that time is the height when the plant was planted.
Answer:
348 of them are not postgraduates
Step-by-step explanation:
Answer:
-25
Step-by-step explanation:
2a² - 5a + 4, for f(-3)
2(-3)² -5(-3)+4
2*(-27)+15+4
-54+19
= -25
Answer:
400 in²
Step-by-step explanation:
(20×16) + (½×8×20)
320 + 80 = 400 in²
Step-by-step explanation:
The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.
Given:
mean, mu = 3550 lbs (hope I read the first five correctly, and it's not a six)
standard deviation, sigma = 870 lbs
weights are normally distributed, and assume large samples.
Probability to be estimated between W1=2800 and W2=4500 lbs.
Solution:
We calculate Z-scores for each of the limits in order to estimate probabilities from tables.
For W1 (lower limit),
Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069
From tables, P(Z<Z1) = 0.194325
For W2 (upper limit):
Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954
From tables, P(Z<Z2) = 0.862573
Therefore probability that weight is between W1 and W2 is
P( W1 < W < W2 )
= P(Z1 < Z < Z2)
= P(Z<Z2) - P(Z<Z1)
= 0.862573 - 0.194325
= 0.668248
= 0.67 (to the hundredth)
