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12345 [234]
3 years ago
7

What function to use and how to use it

Mathematics
1 answer:
Lena [83]3 years ago
7 0

That's the wrong right triangle to draw.  Reading the problem carefully we want this one, figure attached.

So we have the usual 30/60/90 triangle but not to scale.  The sides come in ratio 1:√3:2=x:100:hypotenuse.  So

x = 100/√3 ≈ 57.735

We add that to our 133.2 for the total height of the Cyclone, 190.935.

Answer: 190.9

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The question is basically asking you to get "h" to one side by itself, so...
v=1/3Bh
v/3=Bh
3v/B=h
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3 years ago
For each right triangle below, find the missing side (Pythagorean’s Theorem) and the missing angle (Angle Sum theorem.)
nalin [4]

Answer:     180

i thank hopeful \

6 0
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Read 2 more answers
PLEASEEE HELPPP!!!<br> what is the reason for congruence
Ostrovityanka [42]

Answer:

ASA Hope this helped brainlest pls almost lvled up

Step-by-step explanation:

7 0
3 years ago
Find the maximum and minimum values attained by f(x, y, z) = 5xyz on the unit ball x2 + y2 + z2 ≤ 1.
Allushta [10]
Check for critical points within the unit ball by solving for when the first-order partial derivatives vanish:
f_x=5yz=0\implies y=0\text{ or }z=0
f_y=5xz=0\implies x=0\text{ or }z=0
f_z=5xy=0\implies x=0\text{ or }y=0


Taken together, we find that (0, 0, 0) appears to be the only critical point on f within the ball. At this point, we have f(0,0,0)=0.

Now let's use the method of Lagrange multipliers to look for critical points on the boundary. We have the Lagrangian

L(x,y,z,\lambda)=5xyz+\lambda(x^2+y^2+z^2-1)

with partial derivatives (set to 0)

L_x=5yz+2\lambda x=0
L_y=5xz+2\lambda y=0
L_z=5xy+2\lambda z=0
L_\lambda=x^2+y^2+z^2-1=0

We then observe that

xL_x+yL_y+zL_z=0\implies15xyz+2\lambda=0\implies\lambda=-\dfrac{15xyz}2

So, ignoring the critical point we've already found at (0, 0, 0),


5yz+2\left(-\dfrac{15xyz}2\right)x=0\implies5yz(1-3x^2)=0\implies x=\pm\dfrac1{\sqrt3}
5xz+2\left(-\dfrac{15xyz}2\right)y=0\implies5xz(1-3y^2)=0\implies y=\pm\dfrac1{\sqrt3}
5xy+2\left(-\dfrac{15xyz}2\right)z=0\implies5xy(1-3z^2)=0\implies z=\pm\dfrac1{\sqrt3}

So ultimately, we have 9 critical points - 1 at the origin (0, 0, 0), and 8 at the various combinations of \left(\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3}\right), at which points we get a value of either of \pm\dfrac5{\sqrt3}, with the maximum being the positive value and the minimum being the negative one.
5 0
3 years ago
Rename 120,000 blank ten, thousand
Zolol [24]
One hundred and twenty thousand
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3 years ago
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