To solve this you have to divide 90 by 10 which would be 9 so
t=9
Hope it helps
While x is the number of small shakes and y is the number of large shakes each size shake you by needs to be multiplied by the cost .... D: 3x+5y=479
Let
x---------> the length side of the rectangular area
y---------> the width side of the rectangular area
we know that
the area of the rectangle is equal to

-----> equation 
The perimeter of the rectangle is equal to

but remember that the fourth side of the rectangle will be formed by a portion of the barn wall
so
-----> equation 
<em>To minimize the cost we must minimize the perimeter</em>
Substitute the equation
in the equation 
![P=x+2*[\frac{200}{x} ]](https://tex.z-dn.net/?f=%20P%3Dx%2B2%2A%5B%5Cfrac%7B200%7D%7Bx%7D%20%20%5D%20)
Using a graph tool
see the attached figure
The minimum of the graph is the point 
that means for 
the perimeter is a minimum and equal to 
<u>Find the value of y</u>



The cost of fencing is equal to

therefore
<u>the answer is</u>
the length side of the the fourth wall will be 
Answer:
b = -23.5
Step-by-step explanation:
4.7(3x - 5) = 14.1x - 23.5
<span>y=a((x-h)^2)+k
Vertex=(h,k)
1. Vertex (5,-1) Point (2,4)
y=a((x-5)^2)+(-1)
f(2)=4
4=a((2-5)^2)+(-1)
4=a(-3)^2-1
4=a*9-1
5=a*9
5/9=a
y=(5/9)((x-5)^2)-1
2. Vertex (-2,0) Point (-1,-7)
y=a((x+2)^2)+0
y=a((x+2)^2)
f(-1)=-7
-7=a(-1+2)^2
-7=a(1)^2
a=-7
y=-7(x+2)
(x-h)^2=4(d)(y-k)
3. Vertex (0,0) Focus (0,2)
d=f-v
d=2
(x^2)=4(2)(y)
(x^2)=8y
f(0)=0
4. Focus (-3,4) Directrix y= -2
(x-h)^2=4(d)(y-k)
d=(4-(-2))/2=6/2=3
(x-h)^2=4(3)(y-k)
h=-3
k=(-2+4)/2=(2)/2=1
(x+3)^2=4(3)(y-1)
(x+3)^2=12(y-1)</span>