If you do 13.75-2.90 you're left with 10.85. Divide 3255 by 10.85 you get 300.
300 copies is your answer
Answer:
Step-by-step explanation:
1. Approach
Since it is given that the garden box is a rectangle, then the opposite sides are congruent. One can use this to their advantage, by setting up an equation that enables them to solve for the width of the rectangle. After doing so, one will multiply the width by the given length and solve for the area.
2. Solve for the width
It is given that the garden box is a rectangle. As per its definition, opposite sides in a rectangle are congruent. The problem gives the length and the perimeter of the rectangle, therefore, one can set up an equation and solve for the width.
Substitute,
Conver the mixed number to an improper fraction. This can be done by multiplying the "number" part of the mixed number by the denominator of the fraction. Then add the result to the numerator.
Inverse operations,
3. Solve for the area
Now that one has solved for the width of the box, one must solve for the area. This can be done by multiplying the length by the width. Since the width is a fraction, one must remember, that when multiplying an integer by a fraction, one will multiply the integer by the numerator (the top of the fraction), and then simplify by reducing the fraction, if possible. Reducing the fraction is when one divides both the numerator and the denominator by the GCF (Greatest Common Factor).
Substitute,
A Reindeer does on its back and it lives in the north pole!
Answer:
2.3 ft
Step-by-step explanation:
We can take the total length of the original piece and divide it into 3 for the 3 equal parts.
3.6 ft / 3 parts = 2.3 ft
sine:<span> the trigonometric function that is equal to the ratio of the side opposite a given angle (in a right triangle) to the hypotenuse.
</span>cosine: the trigonometric function that is equal to the ratio of the side adjacent to an acute angle (in a right-angled triangle) to the hypotenuse.
tangent: <span>a straight line or plane that touches a curve or curved surface at a point, but if extended does not cross it at that point.</span>