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WINSTONCH [101]
3 years ago
9

Can anyone help me solve this Algebra 2 Problem, i literally cant figure it out

Mathematics
1 answer:
Andrews [41]3 years ago
5 0

Answer:

Zeros : 1 , -1, 3

Degree : 4

End Behaviour : At x-> ∞ f(x) -> ∞ and x->-∞ f(x) -> ∞

Y - intercept : -3

Extra Points: (0,-3), (2,-3)

Step-by-step explanation:

f(x) = 0 to find the zeros

Therefore (x+1)(x-1)^{2} (x-3) = 0

Clearly x = -1,1,3

Here 1 is a repeating root as it is (x-1)²

Degree is highest power of x in f(x)

Clearly it is x*x²*x = x⁴ is the maximum power of x

Thus degree is 4

Looking at end behavior we substitute x->∞ and x-> -∞

Clearly f(x)>0 as all terms are positive and f(x)->∞

Similarly when x->-∞

f(x)>0 as 2 terms are -ve and their product is positive thus f(x)-> ∞

Y-Intercept is f(0)

f(0) = (0+1)(0-1)²(0-3) = 1*1*-3 = -3

Thus Y-Intercept is -3

Substitute x = 0 , 2 for extra points

Thus f(0) = -3

and f(2) = -3

Thus points on the graph (0,-3), (0,2)

We can use all this information to draw a graph remember that 1 is a repeating root so that will be a point of minima. The graph is a parabola that passes through x-axis at x = -1, 3.

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Revenue from Monorail Service, Las Vegas In 2005 the Las Vegas monorail charged $3 per ride and had an average ridership of abou
Karolina [17]

Answer:

A)The required linear demand equation ( q ) = -4500p + 41500

B) $4.61

   $95680.55

C) No it would not have been possible by charging a suitable price

Step-by-step explanation:

<u>A)  find the linear demand equation</u>

given two points ; ( 3, 28000 ) and ( 5, 19000 )

slope ( m ) = ( y2 - y1 ) / ( x2 - x1 )

                 = ( 19000 - 28000 ) / ( 5 - 3 )  = -4500

slope intercept is represented as ; y = mx + b

where y( 28000) = -4500(3) + b

  hence b = 41500  

hence ; y = -4500x + 41500

The required linear demand equation ( q ) = -4500p + 41500   ----- ( 1 )

p = price per ride

<u>B ) Determine the price the company should charge to maximize revenue from ridership  and corresponding daily revenue</u>

Total revenue ( R ) = qp

                               = p ( -4500p + 41500 )

  hence R = -4500p^2 + 41500p  ------ ( 2 )

To determine the price that should maximize revenue from ridership we will equate R = -4500p^2 + 41500p  to a quadratic equation R(p) = ap^2 + bp + c

where a = -4500 ,  b = 41500 , c = 0

hence p = -\frac{b}{2a}  = - \frac{41500}{2(-4500)} =  4.61

$4.61 is the price the company should charge to maximize revenue from ridership

corresponding daily revenue = R = -4500p^2 + 41500 p

where p = $4.61

hence R = -4500(4.61 )^2 + 41500(4.61) = $95680.55

C) No it would not have been possible by charging a suitable price

5 0
2 years ago
How do I solve numbers 8 and 9?
Tresset [83]
8: 20
9: 90
I am so sorry if this is wrong. I am not good at this type of things
7 0
2 years ago
Are the following lines parallel perpendicular or neither y=-5/3x - 5 and y=4/3x - 5​
katrin [286]

Answer:

neither

Step-by-step explanation:

For lines to be parallels the slopes must be equal, for the lines to be perpendicular the lines have to be inverse reciprocals  meaning if you have a slope of 1/2X then the perpendicular line must be -2X

3 0
2 years ago
What are the steps to this?
Evgen [1.6K]

Answer:

B=112

Step-by-step explanation:

Angle B is on the same line as angle A(68). They would need to combine for a total of 180 degrees. So 68-180=112

4 0
3 years ago
Read 2 more answers
A necklace regularly sells for $18.00. the store advertises a 15% discount. what is the sale price of the necklace in dollars
SSSSS [86.1K]
I can solve with 2 methods:

I. Because the discount is 15 % of 18 $ , the price will be (100-15=85) 85 % of 18 $
18*85/100= 15,3 $ ( the sale price)

II. The discount is 15 % of 18$
15*18/100= 2,7$  ( the discount)
then I decrease it from the regularly price
18$-2,7$=15,3 $ (the sale price)

Personally I believe the first is an easier method.
I hope you understand and you can apply this in every similary problem.



6 0
3 years ago
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