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Misha Larkins [42]
3 years ago
8

Please help solve for A

Mathematics
1 answer:
slavikrds [6]3 years ago
7 0

Answer:

Step-by-step explanation:

\frac{sin 82}{28} =\frac{sin A}{8} \\sin A=\frac{8}{28} \times sin 82\\A=sin^{-1} (\frac{2}{7} \times sin~82) \approx 16.4 ^\circ

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PLEASE HELPPPPPPPPPPPP
Evgen [1.6K]

Answer:

V = 13312yd^2

Step-by-step explanation:

32 x 32 x 39 / 3 = volume

32 x 32 x 39 = 39936/3  = 13312 sq yard.

As you can see the formula for Volume is L x W x H / 3

The formula for Area of a pyramid is SA = A + (3/2)bh

We have one rule we work out the square to represent the A then we can find SA. While 3/2 is 1.5 really which is 150% of the height x the base, then we + plus the area of the square.

6 0
3 years ago
(k^4_3_3k^3)+(-5k^3+6k^3_8k^5)
PilotLPTM [1.2K]

Answer:

(k4+3+3k3)+(-5k3+6k3+8k5)

Final result :

 8k5 + k4 + 4k3 + 3

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (((k4)+3)+(3•(k3)))+(((0-(5•(k3)))+(6•(k3)))+23k5)

Step  2  :

Equation at the end of step  2  :

 (((k4)+3)+(3•(k3)))+(((0-(5•(k3)))+(2•3k3))+23k5)

Step  3  :

Equation at the end of step  3  :

 (((k4)+3)+(3•(k3)))+(((0-5k3)+(2•3k3))+23k5)

Step  4  :

Equation at the end of step  4  :

 (((k4) +  3) +  3k3) +  (8k5 + k3)

Step  5  :

Checking for a perfect cube :

5.1    8k5+k4+4k3+3  is not a perfect cube


Trying to factor by pulling out :

5.2      Factoring:  8k5+k4+4k3+3


Thoughtfully split the expression at hand into groups, each group having two terms :


Group 1:  k4+3

Group 2:  8k5+4k3


Pull out from each group separately :


Group 1:   (k4+3) • (1)

Group 2:   (2k2+1) • (4k3)


Bad news !! Factoring by pulling out fails :


The groups have no common factor and can not be added up to form a multiplication.


Polynomial Roots Calculator :

5.3    Find roots (zeroes) of :       F(k) = 8k5+k4+4k3+3

Polynomial Roots Calculator is a set of methods aimed at finding values of  k  for which   F(k)=0  


Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  k  which can be expressed as the quotient of two integers


The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient


In this case, the Leading Coefficient is  8  and the Trailing Constant is  3.


The factor(s) are:


of the Leading Coefficient :  1,2 ,4 ,8

of the Trailing Constant :  1 ,3


Let us test ....


  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        -8.00    

     -1       2        -0.50        2.31    

     -1       4        -0.25        2.93    

     -1       8        -0.13        2.99    

     -3       1        -3.00       -1968.00    

     -3       2        -1.50        -66.19    

     -3       4        -0.75        -0.27    

     -3       8        -0.38        2.75    

     1       1        1.00        16.00    

     1       2        0.50        3.81    

     1       4        0.25        3.07    

     1       8        0.13        3.01    

     3       1        3.00        2136.00    

     3       2        1.50        82.31    

     3       4        0.75        6.90    

     3       8        0.38        3.29    


Polynomial Roots Calculator found no rational roots


Final result :

 8k5 + k4 + 4k3 + 3

Step-by-step explanation:


6 0
3 years ago
44 points...<br> Multiply.<br> 3/5⋅3/4<br><br> a 9/20<br><br> b 4/10<br><br> c 4/5<br><br> d 5/4
enyata [817]

Answer:

the answer is a

Step-by-step explanation:

3 times 3 is 9, 5 times 4 is 20

9/20

3 0
3 years ago
Hey i need this answer quick
Ad libitum [116K]

Answer:

12x10x5+11x11=721

Step-by-step explanation:

5 0
3 years ago
Evaluate 3z when z=9
sweet-ann [11.9K]
Z=9 so 3*9 is 27. 27 is your answer. You are literally just switching the variable z with 9.
3 0
3 years ago
Read 2 more answers
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