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maxonik [38]
2 years ago
12

you want to implement a protocol on your network that allows computers to find the ip address of a host from a logical name. whi

ch protocol should you implement?
Computers and Technology
1 answer:
aniked [119]2 years ago
7 0

The protocol that should be implemented is that one needs to enable hosts on the network to find the IP address.

<h3>What is IP address?</h3>

It should be noted that IP address simply means a unique address that defines a device on the internet.

In this case, the protocol that should be implemented is that one needs to enable hosts on the network to find the IP address.

Learn more about IP address on:

brainly.com/question/24930846

#SPJ12

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Explanation:

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For a new version of processor, suppose the capacitive load remains, how much more energy will the processor consume if we incre
xxMikexx [17]

Answer:

72.80 % more energy will be consumed.

Explanation:

First of all, let us have a look at the formula of energy for a processor.

E = CV^2f

Where, E is the energy

C is the capacitance

V is the voltage and

f is the clock rate.

Let E_1 be the energy of older processor.

C_1 be the capacitance of older processor.

V_1 be the voltage of older processor

f_1 be the capacitance of older processor

So, E_1 = C_1V_1^2f_1 ....... (1)

and

Let E_2 be the energy of newer processor.

C_2 be the capacitance of newer processor.

V_2 be the voltage of newer processor

f_2 be the capacitance of newer processor

E_2 = C_2V_2^2f_2 ....... (2)

Dividing equation (2) with equation (1):

\dfrac{E_2}{E_1} = \dfrac{C_2V_2^2f_2}{C_1V_1^2f_1}

As per given statement:

C_1=C_2

V_2=1.2\times V_1

f_2=1.2\times f_1

Putting the values above:

\dfrac{E_2}{E_1} = \dfrac{C_1\times (1.2V_1)^2\times 1.2f_1}{C_1V_1^2f_1}\\\Rightarrow \dfrac{E_2}{E_1} = \dfrac{(1.2)^2\times 1.2}{1}\\\Rightarrow \dfrac{E_2}{E_1} = 1.728\\\Rightarrow \bold{E_2 = 1.728 \times E_1}

Energy consumed by newer processor is <em>1.728 </em>times the energy consumed by older processor.

OR

<em>72.80 %</em> more energy will be consumed by the newer processor.

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