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PtichkaEL [24]
2 years ago
13

"\huge\fbox\green{question}" align="absmiddle" class="latex-formula">
#Combine the members of the following sets to from new sets.Show the members in diagrams

a)A={Mine,Shine,Hari} and B={Ram,Sita,Dolma}

b)M={3,6,9,12>and N={5,10,15,20}

c)A={Mari,Rahlm,Bishnu}and B={Bishnu, Kishan,Dorge}

d)C={4,8,12,16,20} and F={8,16,24,32}​
Mathematics
1 answer:
Aloiza [94]2 years ago
8 0

Refer to the attachment

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Which graph represents the function f(x)=−4x−3?
Evgen [1.6K]
<h2>Answer:</h2>

The graph on the top left.

<h2>Step-by-step explanation:</h2>

f(x) = -4^x - 3

That means that when x = 0...

f(0) = -4^0 - 3

f(0) = -1 - 3

f(0) = -4

So, the function will have a point at (0, -4). We can eliminate the two graphs on the right.

When x = 1...

f(1) = -4^1 - 3

f(1) = -4 - 3

f(1) = -7

So, the function will have a point at (1, -7). That corresponds to the graph on the top left.

<h2>Hope this helps! </h2>
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4 years ago
Is (0,0) a solution to this system? y ≤ x^2 + x - 4 y &lt; x^2 + 2x + 1
yaroslaw [1]

( 0,0 ) is not the solution of the first inequality y≤x² +x-4 but ( 0,0) is the solution for the second inequality y <x²+2x+1.

<h3>What is inequality?</h3>

The relation between two expressions that are not equal, employing a sign such as ≠ ‘not equal to’, > ‘greater than, or < ‘less than’

Finding the solution for the inequality is as follows:-

y ≤  x² +x-4 by putting x and y equal to 0.

0 ≤ 0 + 0 -4

0 ≤ - 4

This is incorrect so (0,0) can not be the solution for this inequality.

y < x²+2x+1.

0 < 0 + 0 + 1

0 < 1

This inequality is showing the solution for (0,0)

Therefore ( 0,0 ) is not the solution of the first inequality y≤x² +x-4 but ( 0,0) is the solution for the second inequality y <x²+2x+1.

To know more about inequality follow

brainly.com/question/24372553

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2 years ago
Find the gcf for the list. 28y4, 20y3
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GCF of 28y^4 and 20y^3 is 4y^3
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Answer:

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3 years ago
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How do you turn a decimal into a fraction
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you put it over 1 and divide it by 10

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