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2 years ago

Find the midpoint of the line segment between the points (11, -5) and (-3, -7)

Mathematics

1 answer:

alexdok [17]2 years ago

4 0

Answer:

(4, -6)

Step-by-step explanation:

(x1+x2)/2 + (y1+y2)/2 = midpoint

(11+-3)/2 = 8/2 = 4. x = 4

(-5 + -7)/2 = -12/2. y = -6

4, -6 is the midpoint

give brainliest please! hope this helps :)

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What is the area of the triangle formed from (0,-1) (0,-4) (4,-1)

bogdanovich [222]

Area of the triangle = (1/2)(base)(height) = (1/2)(4)(5) = 10 square units.
The correct answer is A.

6 0

3 years ago

Read 2 more answers

Find the least common denominator. Then express each fraction using the least common denominator.

Rudiy27

Answer:

THE LCM OF 15 AND 20 IS 60

1/60 AND 3/60

Step-by-step explanation:

5 0

3 years ago

Can someone answer this for me

Anastaziya [24]

X=60° (equilateral triangle)

y=120°
Working: (360°-120°)/2

6 0

3 years ago

a landscaping company needs 160 gallons of 40% fertilize the shrubs in an office park. They have in stock 50% fertilizer and 30%

Novay_Z [31]

Let

x--------> volume of 50% fertilizer

y--------> volume of 30% fertilizer

we know that

x+y=160-----> x=160-y-----> equation 1

x*0.5+y*0.3=160*0.4-----> equation 2

substitute equation 1 in equation 2

[160-y]*0.5+0.3*y=63.8----> 77-0.35*y+0.25*y=63.8

0.10*y=13.2------> y=13.2/0.10----> y=132 gal

x=220-y----> x=220-132----> x=88 gal

the answer is

88 gal of 50% fertilizer

132 gal 30% fertilizer

5 0

3 years ago

Drag each tile to the correct box.

Anni [7]

Answer:

$3x^{2}y^{2}\sqrt[4]{7xy^{3}}$ .

Step-by-step explanation:

Since we have to find the simplified form of the expression as below

$\sqrt[4]{567x^{9}y^{11}}$

we will solve the expression as below

$=[567x^{9}y^{11}]^{\frac{1}{4}}$

$=(81\times 7)^{\frac{1}{4}}\times x^{\frac{9}{4}}\times y^{\frac{11}{4}}$

$=81^{\frac{1}{4}}.7^{\frac{1}{4}}.x^{\frac{8}{4}+\frac{1}{4}}.y^{\frac{8}{4}+\frac{3}{4}}$

$=(3^{4})^{\frac{1}{4}}.7^{\frac{1}{4}}.x^{2+\frac{1}{4}}.y^{2+\frac{3}{4}}$

$=3^{1}.7^{\frac{1}{4}}.x^{2}.x^{\frac{1}{4}}.y^{2}.y^{\frac{3}{4}}$

$=3.x^{2}.y^{2}.(7^{\frac{1}{4}}.x^{\frac{1}{4}}.y^{\frac{3}{4}})$

$=3x^{2}y^{2}.(7xy^{3})^{\frac{1}{4}}$

$=3x^{2}y^{2}\sqrt[4]{7xy^{3}}$ .

7 0

3 years ago