Answer:
ABOVE the x-axis
Step-by-step explanation:
Please use "^" to denote exponentiation: y = x^2 + 2x + 3
To find the vertex, we must complete the square of y = x^2 + 2x + 3, so that we have an equivalent equation in the form f(x) = (x - h)^2 + k.
Starting with y = x^2 + 2x + 3,
we identify the coefficient of x (which is 2), take half of that (which gives
us 1), add 1 and then subtract 1, between "2x" and "3":
y = x^2 + 2x + 1 - 1 + 3
Now rewrite x^2 + 2x + 1 as (x + 1)^2:
y = (x + 1)^2 - 1 + 3, or y = (x + 1)^2 + 2. Comparing this to f(x) = (x - h)^2 + k, we see that h = 1 and k = 2. This tells us that the vertex of this parabola is at (h, k): (1, 2), which is ABOVE the x-axis.
69.92 when you add them all up and divide it you get 69.92
Answer:
B) Graph B only.
Step-by-step explanation:
Table A is not correct, because:
In Y = 2X, replacing each row:
3 =/= 2 x 2
6 =/= 2 x 4
9 =/= 2 * 6
Table B is correct, because:
When Y is 2, X is 1 which is equal to 2x1.
When Y is 4, X is 2 which is equal to 2x2.
6 tens is the same as 60 so....
60 x 10 = 600
