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marysya [2.9K]
3 years ago
6

−1/8(2h+4)+12=−7/4 What is h?

Mathematics
1 answer:
vaieri [72.5K]3 years ago
3 0
H=53....factor expression
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6:5

Step-by-step explanation:

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For tall heterozygotes with antennae, the offspring are:
Misha Larkins [42]

Recombinant frequency between T and A is 12%

<u>Explanation:</u>

<u></u>

Two characters are considered - height and antennae

Traits of height - Tall and Dwarf

Traits of antennae - Antennae and No antennae

<u>Given:</u>

<u />

Tall-antennae (46) and dwarf-no antennae (42) are the wild type.

Dwarf- antennae (7) and tall- no antennae (5) are the recombinants.

Total possibilities = 100

Recombinant frequency = \frac{7}{100} + \frac{5}{100}

Recombinant frequency = \frac{12}{100}

Recombinant frequency in percentage = \frac{12}{100} X 100 = 12%

Therefore, recombinant frequency between T and A is 12%

8 0
3 years ago
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