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2 years ago

Pls help me with this problem :)

Mathematics

2 answers:

iVinArrow [24]2 years ago

8 0

Answer:

The answer is 4 and 2/3 cm²

Step-by-step explanation:

Take the square root of 49 and 9 and you'll get 7 and 3 since the scale factor is the large area over the small area.

The large area would be √49 cm²

The small area would be √9 cm²

7 x cm

------ = ----------, cross multiply

3 2 cm

7 × 2 = 3 × x

14 = 3x

x = 14/3, x = 4 and 2/3

vagabundo [1.1K]2 years ago

6 0

Answer:

I believe it should be rounded to 11, if not decimal would be 10.88

Step-by-step explanation:

49 divided by 9 equals 5.44 which is the amount times the 49cm^2 triangle is compared to the 9cm^2. So then the side is 2cm, multiply by the amount times bigger the other triangle is which would be 10.88. Hopefully I'm not wrong:)

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3x + 2(4x − 6) = 8x + 1

professor190 [17]

3x+8x-12=8x+1
11x-12=8x+1
3x=13
X=13/3.

4 0

4 years ago

Read 2 more answers

Can somebody help me with this question?

V125BC [204]

Answer:

$\frac{2}{5}\vec{a}+\vec{b}$

Step-by-step explanation:

$\vec{DE}=\vec{DB}+\vec{BE}$

$=\frac{3}{5}\vec{OB}+\frac{1}{5}\vec{BC}$ $\left\{OD:DB=2:3,BE:EC=1:4\right\}$

$=\frac{3}{5}\left(\vec{OA}+\vec{AB}\right)+\frac{1}{5}\left(\vec{BA}+\vec{AO}+\vec{DC}\right)$

$=\frac{3}{5}\left(\vec{a}+\vec{b}\right)+\frac{1}{5}\left(-\vec{b}-\vec{a}+\vec{3b}\right)$

$=\frac{2}{5}\vec{a}+\frac{2}{5}\vec{b}+\frac{3}{5}\vec{b}$

$=\frac{2}{5}\vec{a}+\vec{b}$

I hope this helps you

:)

8 0

3 years ago

Identify the solution of the system -3x -4y=2 8y=-6x-4

yarga [219]

-3x - 4y = 2
8y = -6x - 4
8 8
 y = -0.75x - 0.5

-3x - 4(-0.75x - 0.5) = 2
-3x + 3x + 2 = 2
0x + 2 = 2
 - 2 - 2
 0x = 0
 0 0
 x = 0
-3(0) - 4y = 2
 0 - 4y = 2
 - 0 - 0
 -4y = 2
 -4 -4
 y = 0.5
 (x, y) = (0, 0.5)

5 0

3 years ago

A man is planning to take his vacation in three weeks. He determines that there is a 15% chance of rain on any given day in that

mixas84 [53]

Answer: 15%

Explanation: if it has 15% chance of rain on any given day so that’s 15% chance on every day that week and I’d think about rescheduling that vacation for another week

4 0

3 years ago

A model rocket is launched with an initial upward velocity of 100 ft/s. The rocket's height h (in feet) after t seconds is given

tamaranim1 [39]

$\bf \stackrel{h}{34}=100t-16t^2\implies 16t^2-100t+34=0\\\\\\ 8t^2-50t+17=0
\\\\\\
~~~~~~~~~~~~\textit{quadratic formula}
\\\\
\stackrel{\stackrel{a}{\downarrow }}{8}t^2\stackrel{\stackrel{b}{\downarrow }}{-50}t\stackrel{\stackrel{c}{\downarrow }}{+17}=0
\qquad \qquad 
t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}$

$\bf t=\cfrac{ - (-50) \pm \sqrt { (-50)^2 -4(8)(17)}}{2(8)}\implies t=\cfrac{50\pm \sqrt{2500-544}}{16}
\\\\\\
t=\cfrac{50\pm\sqrt{1956}}{16}\implies t=\cfrac{50\pm\sqrt{4\cdot 489}}{16}\implies t=\cfrac{50\pm\sqrt{2^2\cdot 489}}{16}
\\\\\\
t=\cfrac{50\pm 2\sqrt{489}}{16}\implies t=\cfrac{25\pm \sqrt{489}}{8}\implies t\approx
\begin{cases}
5.88916805\\
0.36083195
\end{cases}$

4 0

3 years ago