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3 years ago

Identify the solution of the system -3x -4y=2 8y=-6x-4

1 answer:

5 0

-3x - 4y = 2
8y = -6x - 4
8 8
 y = -0.75x - 0.5

-3x - 4(-0.75x - 0.5) = 2
-3x + 3x + 2 = 2
0x + 2 = 2
 - 2 - 2
 0x = 0
 0 0
 x = 0
-3(0) - 4y = 2
 0 - 4y = 2
 - 0 - 0
 -4y = 2
 -4 -4
 y = 0.5
 (x, y) = (0, 0.5)

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Que is on pic.i can't able to type in text.

ad-work [718]

It's not difficult to compute the values of $A$ and $B$ directly:

$A=\displaystyle\int_1^{\sin\theta}\frac{\mathrm dt}{1+t^2}=\tan^{-1}t\bigg|_{t=1}^{t=\sin\theta}$
$A=\tan^{-1}(\sin\theta)-\dfrac\pi4$

$B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt$
$B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}$
$B=\ln\left|\dfrac{\csc\theta}{\sqrt{1+\csc^2\theta}}\right|+\dfrac12\ln2$

Let's assume $0$ , so that $|\csc\theta|=\csc\theta$ .

Now,

$\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}$
$\Delta=A\begin{vmatrix}B^2&-1\\A^2+B^2&-1\end{vmatrix}-e^{A+B}\begin{vmatrix}A^2&B\\A^2+B^2&-1\end{vmatrix}+\begin{vmatrix}A^2&B\\B^2&-1\end{vmatrix}$
$\Delta=A(-B^2+A^2+B^2)-e^{A+B}(-A^2-A^2B-B^3)+(-A^2-B^3)$
$\Delta=A^3-A^2-B^3+e^{A+B}(A^2+A^2B+B^3)$

There doesn't seem to be anything interesting about this result... But all that's left to do is plug in $A$ and $B$ .

3 0

3 years ago

The angle measures associated with which set of ordered pairs share the same reference angle? (Negative StartFraction StartRoot

Katarina [22]

Answer:

$(C)\left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)$

Step-by-step explanation:

The reference angle is the angle that the given angle makes with the x-axis.

For an ordered pair to share the same reference angle, the x and y coordinates must be the same or a factor of each other.

From the given options:

$(A)\left(-\dfrac{\sqrt{3} }{2} ,-\dfrac{1 }{2}\right)$ and \left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)\\\\(B)\left(\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(-\dfrac{\sqrt{3} }{2}, \dfrac{1 }{2}\right)\\\\(C)\left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)\\\\(D)\left(\dfrac{\sqrt{3} }{2},\dfrac{1 }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)$

We observe that only the pair in option C has the same x and y coordinate with the second set of points being a negative factor of the first term. Therefore, they have the same reference angle.

5 0

3 years ago

Read 2 more answers

The ratio of kangaroos to koalas in the Australian zoo is 6 to 8 . If there are 132 koalas in the zoo how many kangaroos are in

dolphi86 [110]

Answer:

Step-by-step explanation:

set it up as a proportion 6/8 = x/132. then solve

8 0

3 years ago

Guys help they want me to put a picture what do i do

tatiyna

Answer:

Step-by-step explanation:

A U.S. penny is considered to be 1/16th of an inch thick (1.5875 mm) so there are 16 per inch or 192 per foot (plus or minus).

Hope this helps!

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Have a great day!

7 0

2 years ago

Select the correct location on the table. Consider the following equations. f(x)= (x^2+3x+2)/(x+8) and g(x)= (x-1)/x. Approximat

zhannawk [14.2K]

Answer:

(b) -61/16 | -15/4

Step-by-step explanation:

We assume you're using a binary search successive approximation technique that starts with an interval and cuts it in half with each iteration. The final approximation of the solution to the equation will be the midpoint of the interval after it has been cut in half 3 times.

The graph shows the intersection point of the curves lies between x = -4 and x = -3.

If we define h(x) = f(x) -g(x), then our first iteration will evaluate h(-7/2) and determine which end of the interval gets replaced. The attachment shows us that the sign of h(-7/2) is the same as the sign of h(-3), so -7/2 replaces -3 and the interval after the first iteration is [-4, -7/2].

The midpoint of this interval is -15/4. The sign of h(-15/4) is the same as the sign of h(-7/2), so the interval after the second iteration is [-4, -15/4].

The midpoint of this interval is -31/8. The sign of h(-31/8) is the same as the sign of h(-4), so the interval containing the solution after the third iteration is [-31/8, -15/4]. The approximate solution value after 3 iterations is (-31/8 -15/4)/2 = -61/16.

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You can read more at ...

brainly.com/question/26463478

4 0

2 years ago