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sashaice [31]
2 years ago
5

52/10 Convert to mixed numbers

Mathematics
2 answers:
dolphi86 [110]2 years ago
5 0

Answer:

5 \times \frac{2}{10}

Step-by-step explanation:

The number of times 10 can go in 52 will be the whole number

5 \times \frac{?}{?}

10 will go in 52 5times which will be 50 remainder two.The remainder will be the numerator

5 \times \frac{2}{?}

The denominator will be the original denominator (the number below)

5 \times \frac{2}{10}

lina2011 [118]2 years ago
4 0

Reduce the expression 52/1 by eliminating common factors.

Factor 2 out of 52.

  • \bf{\dfrac{2(26)}{10} }

Factor 2 out of 10.

  • \bf{\dfrac{2\cdot26}{2\cdot5}  }

Cancel the common factor.

  • \bf{\dfrac{\not{2}\cdot26}{\not{2}\cdot5}  }

Substitute the expression.

  • \bf{\dfrac{26}{5}  }

Fit the division problem into long division format.

               \begin{matrix}\:\:\:\:\:\:\emptyspace5\:\:\:\:\:\:\:\:\:\:\:\\ 5\overline{|\smallspace26.}\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\underline{\emptyspace2\emptyspace5}\:\:\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\emptyspace1\emptyspace\:\:\:\:\:\:\:\:\:\:\end{matrix}

The result of the division 26/5 is 5 with a remainder of 1.

\bf{5 \ r \ 1 }

Use the long division solution to convert the original fraction,\bf{\left(\dfrac{26}{5}\right)  } in a mixed number. The integer part of the mixed number will be the number of times the denominator of the original fraction integer divides the numerator of the original fraction, (5), and the fractional part of the mixed number will be the remainder of the original division (1) Enter the denominator of the original fraction, (5).

\bf{5\dfrac{1}{5} \ \ \to \ \ \ Answer }

\huge \red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}

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Answer:

The proportion of chips that do not fail in the first 1000 hours of their use is 52%.

Step-by-step explanation:

The claim made by the company is that 52% of the chips do not fail in the first 1000 hours of their use.

A quality control manager wants to test the claim.

A one-proportion <em>z</em>-test can be used to determine whether the proportion of chips do not fail in the first 1000 hours of their use is 52% or not.

The hypothesis can be defined as:

<em>H₀</em>: The proportion of chips do not fail in the first 1000 hours of their use is 52%, i.e. <em>p</em> = 0.52.

<em>Hₐ</em>: The proportion of chips do not fail in the first 1000 hours of their use is different from 52%, i.e. <em>p</em> ≠ 0.52.

The information provided is:

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The test statistic value is:

z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.49-0.52}{\sqrt{\frac{0.52(1-0.52)}{900}}}=-1.80

The test statistic value is -1.80.

Decision rule:

If the <em>p-</em>value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the <em>p</em>-value as follows:

p-value=2\times P(Z

*Use a <em>z</em>-table.

The <em>p</em>-value = 0.07186 > <em>α</em> = 0.02.

The null hypothesis was failed to be rejected at 2% level of significance.

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The proportion of chips that do not fail in the first 1000 hours of their use is 52%.

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I think the answer is (C)
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