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Maru [420]
2 years ago
7

Solve the compound inequality 6b < 24 or 4b + 12 > 4.

Mathematics
1 answer:
myrzilka [38]2 years ago
3 0
The answer is a. b>-2 because

6b<24
b< 24/6
b<4


And

4b+12>4
4b>4-12
4b>-8
b>-8/4
b>-2
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andrew-mc [135]
Tan t= 8/15
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3 years ago
-22<br> 52<br> -33<br> 71<br> -44<br> What is the x-intercept of the line?
swat32

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30

Step-by-step explanation:

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I NEED ANSWER ASAP! I WILL GIVE BRAINELIEST!!!!!! Construct a right triangle whose legs are in the ratio 3:4. What are the ratio
Gala2k [10]

Answer:

3 : 5, 4: 5

Step-by-step explanation:

Let the common multiplier of the given ratios be x.

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By Pythagoras Theorem:

{hyp}^{2}  =  {(3x)}^{2}  +  {(4x)}^{2}   \\  = 9 {x}^{2}  + 16 {x}^{2}  \\  = 25 {x}^{2}  \\  hyp =  \sqrt{25 {x}^{2} }  \\ hyp = 5x \\  \\ ratios \:  of each \:  leg  \: to  \: the \:  hypotenuse \\  \frac{3x}{5x}  = 3  : 5 \\  \\  \frac{4x}{5x}  = 4 : 5

5 0
3 years ago
A corporate team-building event costs $19plus an additional $1 per attendee. How many attendees can there be, at most, if the bu
Mars2501 [29]

Answer:

There can be at most 12 attendees in a corporate team-building event.

Step-by-step explanation:

Let x denotes number of attendees in a corporate team-building event.

Fixed cost = $19

Cost charged per attendee = $1

Budget for the corporate team-building event = $31

Therefore,

19+1(x)\leq 31\\19+x\leq 31\\x\leq 31-19\\x\leq 12

So, there can be at most 12 attendees in a corporate team-building event.

8 0
3 years ago
Mr eliot is extremely careful with his money. He recently invested part of his $150,000 life savings in gold bullion and the res
DIA [1.3K]

Answer:

The amount invested in gold bullion by Mr. Eliot  =   $50,000

Step-by-step explanation:

Total amount of savings Me. Eliot ha s = $150,000

Let us assume the amount invested in gold bullion = $m

So, the amount invested in bank = $150,000 - m

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So, the profit in gold bullion  =  0.05 m

and 3% on (150,000 -m)   = \frac{3}{100}  \times  (150,000 -m) = 0.03  (150,000 -m)

= 4,500 - 0.03 m

So, the profit in bank =  4,500 - 0.03 m

Now,  the total profit  = $5,500

⇒Profit from gold bullion + ban = $5,500

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or, 0.02 m = 1000

⇒ m = 1000/0.02 = 50,000

Hence, the amount invested in gold bullion  =  m = $50,000

3 0
3 years ago
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