Answer:
12.5%
Step-by-step explanation:
5/40 = .125
.125×100 = 12.5%
Answer:
x=ln(61)/ln(4)
Step-by-step explanation:
4^x+3=64
4^x=64-3
4^x=61
x=ln(61)/ln(4)
Answer:
U=76 and R=42 so they are not
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Answer:
The probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% is 0.6923.
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:

The standard deviation of this sampling distribution of sample proportion is:

The information provided is:
<em>p</em> = 0.60
<em>n</em> = 100
As <em>n</em> = 100 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample proportions.
The distribution of sample proportion is
.
Compute the probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% as follows:


Thus, the probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% is 0.6923.
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